The earliest start time rule "compares the finish times for all immediate predecessors of an activity".
<u>Option: B</u>
<u>Explanation:</u>
The equation used only to measure Early Start and Early Finish dates:
Early Start of Operation = Predecessor Early Finish operation + 1.
Early Activity End = Period of Activity + Early Activity Start - 1.
The above given terms are basically dependent on how early a project or an operation may start by having all necessary element like how early a task can be started in given time duration. In same how early a work can be finished in business or another sector with in a given time duration. This helps to calculate a millage of a work performed.
Answer: a temporary marked decrease in the birth rate.
Explanation:
Answer:
A. Coverage includes trees, plants, outside antennas and signs that are not attached to the building
Explanation:
The coverage of the Builders Risk Coverage Form solely apply only to the structures under construction, and the materials intended to become a part of the structure, and temporary structures used in the construction
<span>Oogenesis is the creation of the female gamete and spermatogenesis is the creation of the male gamete.
Meiosis begins in male once they reach puberty (they do both meiosis I and II) and do it for the rest of their lives non-stop
Females begin Meiosis I in the womb and they don't start to do Meiosis II until they reach puberty. Unlike males, females don't form gametes non stop and they stop forming gametes at menopause.
The end result for males are four sperm cells
For females, they create three small polar bodies and one big daughter cell. The polar bodies give themselves up and give their nutrients to the big cell. So for females, they create only one gamete while males create four.
I hope this is helpful =)</span>
Aquarium 1 will hold 5 small fish for every 10 gallons of water. If there are 200 gallons in the tank, you can sent up a proportion:
5 small fish/10 gallons = x small fish/ 200 gallons
if you cross multiply, you get
10x = 200 × 5
10x = 1000
x = 100
100 small fish will be in 200 gallons of water.
Aquarium 2 will hold 8 large fish for every 40 gallons of water. A proportion can also be set up here:
8 large fish/ 40 gallons = x large fish/ 200 gallons
if you cross multiply, you get:
40x = 200 × 8
40x = 1600
x = 40
40 large fish will be in 200 gallons of water.
the ratio of small fish to large fish:
100 small fish: 40 large fish
(both are divisible for 10, and if you divide both of them by ten you get)
10 small fish: 4 large fish
you can reduce again, since both are divisble by 2
5 small fish: 2 large fish
