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kirill115 [55]
3 years ago
5

In which quadrant of the coordinate plane is (a - 2, b + 3), if a = -3 and b = 4?

Mathematics
1 answer:
kupik [55]3 years ago
7 0

Answer:Y=X^2-1

Step-by-step explanation:

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What are the eight related addition and subtraction equations for 48, 42, 6
Len [333]

Answer:

Many of these are just the same equation in different orders.

42 + 6 = 48

6 + 42 = 48

48 = 6 + 42

48 = 42 + 6

42 = 48 - 6

48 - 6 = 42

6 = 48 - 42

48 - 42 = 6


6 0
3 years ago
Which equations are true?
Vlad [161]

Answer:

Step-by-step explanation:

1)4.5m+4.7=20m+47

4.5m-20m=47-4.7

-15.5m=42.2

m=-2.72

2)14+21w=7(2+3w)

  41+21w=14+21w

   21w-21w=14-41

3)49r+35=7(7r+35)

  49r+35=49r+245

 49r-49r=245-35

4)9(8h-3)=72h-27

  72h-27=72h-27

   72h-72h=-27+27

5)5.2+5.3t=10+15t

   5.3t-15t=10-5.2

    -9.7t=4.8

      t=4.8/-9.7

      t=0.49

6)6f+3.111=18f-33

  6f-18f=-33-3.111

  -12f=-36.111

     f=-36.111/-12

     f=3.01

7 0
3 years ago
Triangle ΔABC has side lengths of a = 18, <img src="https://tex.z-dn.net/?f=b%3D18%5Csqrt%7B3%7D" id="TexFormula1" title="b=18\s
ozzi

The measure of angle A is 30 degree, the value of tan A is 1/√3 and the area of triangle ABC is 280.6 squared inches.

<h3 /><h3>What is the law of cosine?</h3>

When the three sides of a triangle is known, then to find any angle, the law of cosine is used.

It can be given as,

\angle A=\cos^{-1}\left(\dfrac{b^2+c^2-a^2}{2bc}\right) \\\angle B=\cos^{-1}\left(\dfrac{a^2+c^2-b^2}{2ac}\right) \\\angle C=\cos^{-1}\left(\dfrac{a^2+b^2-c^2}{2ab}\right)

Here, a,b and c are the sides of the triangle and A,B and C are the angles of the triangle.

Triangle ΔABC has side lengths of a = 18, b=18√3  and c = 36 inches.

  • Part A: Determine the measure of angle A

Put the value, in the cosine law, the measure of angle A.

\angle A=\cos^{-1}\left(\dfrac{b^2+c^2-a^2}{2bc}\right) \\\angle A=\cos^{-1}\left(\dfrac{(18\sqrt{3})^2+36^2-18^2}{2(18\sqrt{3})(36)}\right) \\\angle A=0.5236\rm\; rad\\\angle A=30^o\rm\; degree\\

  • Part B: Show how to use the unit circle to find tan A

Using the chart of unit circle, the value of tangent A can be found out. The tangent A is,

\tan A=\tan 30^o\\\tan A=\dfrac{1}{\sqrt{3}}

  • Part C: Calculate the area of ΔABC.

Use the following formula to find area of ΔABC.,

A=\dfrac{ab.\sin C}{2}\\A=\dfrac{18\times18\sqrt{3}.\sin C}{2}\\A=280.6\rm\; in^2

Thus, the measure of angle A is 30 degree, the value of tan A is 1/√3 and the area of triangle ABC is 280.6 squared inches.

Learn more about the law of cosine here;

brainly.com/question/4372174

#SPJ1

7 0
2 years ago
How do you do this question with the given power series?
Sunny_sXe [5.5K]

Step-by-step explanation:

tan⁻¹(x) = ∑ₙ₌₀°° (-1)ⁿ x²ⁿ⁺¹ / (2n+1)

tan⁻¹(1/√3) = ∑ₙ₌₀°° (-1)ⁿ (1/√3)²ⁿ⁺¹ / (2n+1)

tan⁻¹(1/√3) = ∑ₙ₌₀°° (-1)ⁿ (1/√3) (1/√3)²ⁿ / (2n+1)

tan⁻¹(1/√3) = (1/√3) ∑ₙ₌₀°° (-1)ⁿ (1/3)ⁿ / (2n+1)

π/6 = (1/√3) ∑ₙ₌₀°° (-1)ⁿ (1/3)ⁿ / (2n+1)

π = (6/√3) ∑ₙ₌₀°° (-1)ⁿ (1/3)ⁿ / (2n+1)

π = 2√3 ∑ₙ₌₀°° (-1)ⁿ / (3ⁿ (2n+1))

8 0
3 years ago
Ingrid received $110.00 for her birthday and plans to
AnnyKZ [126]
18x6 = 108
110-108 =2
By weeks 6 she will only have $2 left
So being realistic, at week 7 she will have spent all her money.
7 0
3 years ago
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