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Temka [501]
2 years ago
12

Standard deviation 12,16,22,23,34,44,46,47,48,64,67,73,83,89, round to nearest tenth

Mathematics
1 answer:
RideAnS [48]2 years ago
5 0

Answer: 23.9


Step-by-step explanation:

1. First, you must calculate the mean, as following:

\frac{12+16+22+23+34+44+46+47+48+64+67+73+83+89}{14}=47.71

2. Now, you should substract the means obtained to every single number of the set and then square it. Add all of them:

(12-47.71)^{2}+(16-47.71)^{2}+(22-47.71)^{2}+(23-47.71)^{2}+(34-47.71)^{2}+(44-47.71)^{2}+(46-47.71)^{2}+(47-47.71)^{2}+(48-47.71)^{2}+(64-47.71)^{2}+(67-47.71)^{2}+(73-47.71)^{2}+(83-47.71)^{2}+(89-47.71)^{2}=7984.86

3. The mean of this is:

\frac{7984.8574}{14}=570.35

4. The square root of this result is:

\sqrt{2.52}=23.88

5. To the nearest tenth, the result is: 23.9


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DaniilM [7]

(a) Data with the eight day's measurement.

Raw data:      [60,58,64,64,68,50,57,82],  

Sorted data:  [50,57,58,60,64,64,68,82]

Sample size = 8 (even)

mean            = 62.875

median         = (60+64)/2 = 62

1st quartile   = (57+58)/2 = 57.5

3rd quartile  = (64+68)/2 =  66

IQR = 66 - 57.5 = 8.5

(b) Data without the eight day's measurement.

Raw data:      [60,58,64,64,68,50,57]

Sorted data:  [50,57,58,60,64,64,68]

Sample size = 7 (odd)

mean            = 60.143

median         = 60

1st quartile   = 57

3rd quartile = 64

IQR = 64 -57 = 7

Answers:

1. The average is the same with or without the 8th day's data.  FALSE

2. The median is the same with or without the 8th day's data.  FALSE

3. The IQR decreases when the 8th day is included.                  FALSE

4. The IQR increases when the 8th day is included.                   TRUE

5. The median is higher when the 8th day is included.              TRUE

6 0
3 years ago
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Answer:

8 portraits are going to be used in the display.

Step-by-step explanation:

This problem can be solved as a rule of three problem.

Each yd has 36 inches.

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7 0
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Ty very much! Please help? :))
wlad13 [49]

Answer:

<em>Exact Form: </em>

\frac{8}{3}

<em>Decimal Form: </em>

2.6

<em>Mixed Number Form: </em>

2\frac{2}{3}

Hope this helps :)

<em>-ilovejiminssi♡</em>

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