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V125BC [204]
3 years ago
13

Area of the isosceles triangle

Mathematics
2 answers:
Arlecino [84]3 years ago
8 0

Answer:130

Step-by-step explanation:

you do the base times the height

nataly862011 [7]3 years ago
8 0
The answer is 65

Because for a triangle the formula ALWAYS is 1/2 base x height
Ie. 10 x 13 = 130
130/2 = 65
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Find the volume of the largest circular cone that can<br> beinscribed in a shpere of radius 3.
Aleksandr [31]

Answer:

V =\dfrac{32}{3}\pi

Step-by-step explanation:

given,

radius of sphere = 3

volume of cone:

V = \dfrac{1}{3}\pi r^2h

r is the radius of circular base

h is the height of the cone

here r = x and h = 3 + y

now, volume in term of x and y

V = \dfrac{1}{3}\pi x^2(3+y)

Applying Pythagoras theorem

x² + y² = 3²

x = \sqrt{9-y^2}

V = \dfrac{1}{3}\pi ( \sqrt{9-y^2})^2(3+y)

V = \dfrac{1}{3}\pi ( 9-y^2)(3+y)

V = \dfrac{1}{3}\pi (27 + 9 y - 3 y^2-y^3)

differentiating both side

\dfrac{dV}{dy} =\dfrac{1}{3}\pi ( 9-6y- 3y^2)

for maxima  \dfrac{dV}{dy} = 0

\pi ( 3-2 y - y^2)=0

 y² + 2 y - 3 = 0

(y+3)(y-1)=0

 y = 1,-3

y cannot be negative so, volume at y = 1

V = \dfrac{1}{3}\pi (27 + 9 (1)- 3(1)^2-(1)^3)

V =\dfrac{32}{3}\pi

Hence, the largest cone which can be inscribed in the spheres of the radius 3 has volume  V =\dfrac{32}{3}\pi

5 0
3 years ago
What is the volume of the sphere shown below?
Nina [5.8K]

Answer:

Step-by-step explanation:

r = 12

V = 4*pi * r^3 / 3

V = 4 * 3.14 * 12^3 /3

V = 4 * 3.14 * 1728 / 3

V = 4 * 5425.92 /3

V = 21703.68/3

V = 7234.56

None of the answers look correct.

8 0
3 years ago
Whoever answers this correctly will get brainlist! If you are incorrect, you will still get 5 stars and thanks. When you are don
Xelga [282]
It would be 21/25
:)
7 0
3 years ago
Read 2 more answers
Solve the equation -2/3x - 3/4x =5/6.
goldenfox [79]

common denumerator is 12

-8/12x-9/12x=10/12

-17/12x=10/12 <<multiply by 12

-17x=10

x=-0.59

3 0
3 years ago
Read 2 more answers
Coordinate
Angelina_Jolie [31]

Answer: (43,5)

Step-by-step explanation: did the assignment myself.

3 0
3 years ago
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