Step-by-step explanation:
We have been given that AE=BE and
.
We can see that angle CEA is vertical angle of angle DEB, therefore,
as vertical angles are congruent.
We can see in triangles CEA and DEF that two angles and included sides are congruent.


or
Therefore,
by ASA postulate.
Since corresponding parts of congruent triangles are congruent, therefore CE must be congruent to DE.
The answer is B. CD=KL, DE=LM, EF=MN, and so on
Answer:
Approximately 35, or 34.67
Step-by-step explanation:
You can set up a cosine (adjacent over hypotenuse) equation.
cos38 = x/44
Move the 44 over and plug into the calcultaor.
x = 44cos38
(make sure the mode is on degree and not radian!)
B²-4ac?
<span>5x²+7x-6 = 0 </span>
<span>the form is ax²+bx+c = 0 </span>
<span>a=5, b=7, c=-6 </span>
<span>The discriminant D = b²-4ac </span>
<span>= 7² - 4(5)(-6) = 49 + 120 </span>
<span>= 169 </span>