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FrozenT [24]
3 years ago
10

Which is correct?

Mathematics
2 answers:
Vikentia [17]3 years ago
8 0

Answer:

if my math is right its B

astra-53 [7]3 years ago
5 0

Answer:

B

Step-by-step explanation:

763 is greater 746

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<span>the first one is from walmart which is 5.99$ the other store sells it for 3.49 which one is better to buy

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3 years ago
PLS HELP I WILL BRAINLIEST 15 PTS
Mnenie [13.5K]

Answer:17 dollars per hour per hour

Step-by-step explanation:

Hope this helps

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3 years ago
Forensic specialists can estimate the height of a deceased person from the lengths of the person's bones. These lengths are subs
Lera25 [3.4K]

Answer:

130.2845\leq h\leq 137.7245

Step-by-step explanation:

Given an inequality that relates the height h, in centimeters, of an adult female and the length f, in centimeters, of her femur by the equation

|h - (2.47f + 54.10)| \leq  3.72

If an adult female measures her femur as 32.25 centimeters, we can determine the possible range of her height by plugging f = 32.25cm into the modelled equation as shown:

|h - (2.47(32.25) + 54.10)| \leq  3.72\\|h - (79.9045 + 54.10)| \leq  3.72\\|h - (134.0045)| \leq  3.72\\

If the modulus function is positive then:

h - 134.0045 \leq  3.72\\h \leq 3.71+134.0045\\h\leq 137.7245

If the modulus function is negative then:

-(h - 134.0045) \leq  3.72\\-h+134.0045 \leq 3.72\\-h\leq 3.72-134.0045\\-h\leq -130.2845\\

multiply through by -1

-(-h)\geq  -(-130.2845)\\h\geq 130.2845\\130.2845\leq h

combining the resulting inequalities, the estimate of the possible range of heights will be 130.2845\leq h\leq 137.7245

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3 years ago
What are the coordinates of the treasure? If necessary, round the coordinates to the nearest tenth.
kicyunya [14]
If treasure is midway of two points then treasures point is(x1+x2/2,y1+y2/2)

16+3/2, 21+2/2

Else any point shown byyour options is treasure's point

8 0
3 years ago
Read 2 more answers
1/2 of blank equals 62
Damm [24]

The answer you are looking for is 124.

You can find this answer by simply multiplying 62 by 2.

I hope this helps!

5 0
3 years ago
Read 2 more answers
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