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max2010maxim [7]
3 years ago
13

2^x+5 = 3^1-x use logarithms to solve the exponential equation. round answer to 3 decimal places.

Mathematics
2 answers:
marysya [2.9K]3 years ago
8 0
2^{x+5}=3^{1-x}\ \ \ \ \ /log_2()\\\\log_22^{x+5}=log_23^{1-x}\\\\x+5=(1-x)log_23\\\\x+5=log_23-xlog_23\\\\x+xlog_23=log_23-5\\\\x(1+log_23)=log_23-5\ \ \ \ /:(1+log_23)

x=\frac{log_23-5}{1+log_23}\\-------------\\log_23\approx1.5849625\\----------------\\x\approx\frac{1.5849625-5}{1+1.5849625}\approx-1.321
NeX [460]3 years ago
6 0
2^x+5 = 3^1-x
take log on both sides
(x+5)log2=(1-x)log3
0.3010(x+5) = (1-x)0.4771
0.3010x + 1.5050 = 0.4771 - 0.4771x
0.7781x= -1.0279
x=-1.320

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Let r(t)=⟨t2,1−t,4t⟩. calculate the derivative of r(t)⋅a(t) at t=5, assuming that a(5)=⟨−4,4,−5⟩ and a′(5)=⟨−5,9,3⟩
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3 years ago
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2

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6 0
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4 0
3 years ago
Read 2 more answers
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