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Arturiano [62]
3 years ago
15

A rectangle patio is surrounded on three sides by a fence. If the areas of the patio is 45 m sq and the total of fence is 19m wh

at is the length and width of the patio?
Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0
LW = 45
L + 2W = 19
L = 19-2W

substituting for L :-
W(19-2W) = 45

-2W^2 + 19W = 45

2W^2 - 19W + 45 = 0 
W = 5 or 4.5

If W = 5, L = 9
If W = 4.5, L = 10

So there are 2 possible answers.


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What is the area, in square inches, of the isosceles trapezoid below?
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Answer:

104.8 in^2

Step-by-step explanation:

There are 2 ways to solve this problem.

The 1st way:

Let's make 2 triangles and 1 rectangle:

Rectangle Length = 8.3

Rectangle Width = 8

So, the left out length will be 17.9 - 8.3

=> 9.6

Since, 9.6 cm is for 2 parts.

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So, Height of the Triangle = 8

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Area of the triangle

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There are 2 triangles:

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The area of the trapezoid = 104.8 in^2.

The 2nd way is:

Area of a trapezoid

=> Smaller Base + Larger Base / 2 x Height

=> 8.3 + 17.9 / 2 x 8

=> 26.2 / 2 x 8

=> 13.1 x 8

=> 104.8

The area of the trapezoid is 104.8 in^2

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