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Rina8888 [55]
3 years ago
9

Write the equation of the trigonometric graph.

Mathematics
1 answer:
prohojiy [21]3 years ago
5 0
It need to be bigger
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Please help my slow behind ASAP
Marina CMI [18]
We need to look at the first clue, which is that they are 12th graders.

Add all the numbers in the 12th grade row and you get 68

Then match up the 12th grade row with the math column and the number presented you put over 68 so 28/68

Divided and you get D
6 0
3 years ago
Could someone please explain! I cant figure it out.
qwelly [4]

2^-2 = 1/2^2

so: (1/2^2)*(12*3)-5^3

simplify: (1/4)*36-125

36*(1/4) = 36/4 so: 9-125

subtract: -116

3 0
4 years ago
If the CIRCUMFERENCE of a circle is 163.28, what is the AREA of the circle?
vovangra [49]

Answer:

20,939.00 ft²

Step-by-step explanation:

To solve this you first need to find the radius of the circle.

Circumference (C) = (2)radius (r)

163.28=2r

163.28/2=2r/2

81.64=r

Area of a circle (A) = πr²

A=π(81.64)²

A=π(6665.0896)

A=20938.99652

This can be simplified to 20,939.00 ft²

6 0
3 years ago
What is the area of the figure to the nearest tenth? Answer choices: A) 93.8 in² B) 107.2 in² C) 53.9 in² D) 23.5 in² Please hel
Aneli [31]

Answer:

D)

A=23.5 in^2

Step-by-step explanation:

d*\pi*m*/360

A=16*\pi*168/360

A=23.5 in^2

4 0
4 years ago
Question 3 of 10
MrMuchimi

Answer:

The point-slope form  of the line is:

y + 4 = 4(x+3)

Hence, option B is correct.

Step-by-step explanation:

We know the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

Given

The slope m = 4

From the graph, we can take the point (-3, -4)

So, in our case:

(x₁, y₁) = (-3, -4)

m = 4

now substituting m = 4 and (x₁, y₁) = (-3, -4) in the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

y - (-4) = 4(x - (-3))

y + 4 = 4(x+3)

Therefore, the point-slope form  of the line is:

y + 4 = 4(x+3)

Hence, option B is correct.

  • The graph of the line is also attached.

6 0
3 years ago
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