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Veronika [31]
3 years ago
14

A parallelogram is shown below:

Mathematics
2 answers:
lana66690 [7]3 years ago
7 0

Answer:

a). Area of the parallelogram = 8 cm²

b). Area of both the triangles = 4 cm²

Step-by-step explanation:

a). Area of the given parallelogram ABCD = Base × Height

                                                                 = DC × (Vertical distance between

                                                                              AB and DC)

                                                                 = 9 × \frac{8}{9}

                                                                 = 8 ft²

b). If we decompose this parallelogram into two triangles ΔABC and ADC by a diagonal AC,

Area of both the triangles will be equal.

(Since, diagonal of a parallelogram divides the parallelogram into two equal triangles)

Therefore, area of ΔABC = Area of ΔADC = 4 ft²

Mumz [18]3 years ago
7 0

Answer:

Answer:

a). Area of the parallelogram = 8 cm²

b). Area of both the triangles = 4 cm²

Step-by-step explanation:

a). Area of the given parallelogram ABCD = Base × Height

                                                                = DC × (Vertical distance between

                                                                             AB and DC)

                                                                = 9 ×  

                                                                = 8 ft²

b). If we decompose this parallelogram into two triangles ΔABC and ADC by a diagonal AC,

Area of both the triangles will be equal.

(Since, diagonal of a parallelogram divides the parallelogram into two equal triangles)

Therefore, area of ΔABC = Area of ΔADC = 4 ft²

Step-by-step explanation:

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GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

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3 years ago
Solve the system of linear equations. 3x−2y=1 9x−6y=3
irakobra [83]
Get the y by itself

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Other equation (get y by itself)

-6y= -9x + 3
y=3/2x - 1/2

Use substitution

3/2x-1/2=3/2-1/2

0=0

All real numbers (any value of x makes the equation true)
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Which part of a sphere is the same distance from all points that are on the sphere?
azamat
D) Center I'm sure of it
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I need help with thisss
Yanka [14]
I believe the answer is 18, because 5x3=15, so we can only assume that N is 6x3=18.
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