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3 years ago

How many planets are there

2 answers:

6 0

8 planets in total but 0 because some people consider Pluto to be a planet.

Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune, and Pluto( if you consider it to be)

Hope it helps you.

nalin [4]3 years ago

5 0

There are 9 planets counting Pluto.

Hope this helps ya

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What is the range of the function

fiasKO [112]

Answer:

Step-by-step explanation:

6 0

3 years ago

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

case a) $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

case b) $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

case c) $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

case d) $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

the answer is

$x^{2}-2x-4=0$

5 0

3 years ago

Read 2 more answers

Twice a number (x) is less than 18

pashok25 [27]

2x < 18.
The solution to the inequality would then be x < 9.

5 0

3 years ago

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How many pounds of 65cent coffee must be mixed with 10 pounds of 90cent coffee to make a mixture worth 70 cents per pound? A

trasher [3.6K]

The answer is 90 100%sure it's 90

7 0

3 years ago

X^2 + 16 Factor the polynomial completely

Lelu [443]

Step-by-step explanation:

${x}^{2} + {16} \\ {x}^{2} + {4}^{2} \\(x + 4 {)}^{2} \\ = {x}^{2} + 8x + 16$

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3 years ago