Let's solve this problem step-by-step.
−3(1−2x)=3x+3(x−3)+6
Step 1: Simplify both sides of the equation.
−3(1−2x)=3x+3(x−3)+6
(−3)(1)+(−3)(−2x)=3x+(3)(x)+(3)(−3)+6(Distribute)
−3+6x=3x+3x+−9+6
6x−3=(3x+3x)+(−9+6)(Combine Like Terms)
6x−3=6x+−3
6x−3=6x−3
Step 2: Subtract 6x from both sides.
6x−3−6x=6x−3−6x
−3=−3
Step 3: Add 3 to both sides.
−3+3=−3+3
0=0
So, 0=0 or all real numbers.
Answer:
t = 1, but please check to see if I correctly interpreted your formatting.
Step-by-step explanation:
The format of the question is too confusing.
I'll assume this is the equation to be solved:
<u>16−2t=t+9+4t</u>
<u></u>
16−2t=t+9+4t
16-9 = t + 2t + 4t
7 = 7t
t = 1
Its d!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
1,908
Step-by-step explanation:
