Answer:
2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Explanation:
Given data:
Mass of sample = 142.1 g
Initial temperature = 25.5°C
Final temperature = 46°C
Specific heat capacity of Al = 0.90 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 46°C - 25.5°C
ΔT = 20.5°C
Q = 142.1 × 0.90 J/g.°C × 20.5°C
Q = 2621.75 j
Thus, 2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Answer:
E
Explanation:
E. Amino acids (and thus proteins) also have nitrogen atoms; thus, the radioactivity would not distinguish between DNA and proteins.
Answer:
The Volume of the lungs that would produce 2 mmHg pressure decrease is
Explanation:
From the question we are told that
The volume of air in the lungs is 
The pressure difference for quit normal inspiration is 
The temperature of air in the lungs 
The pressure after normal expiration is at 
From ideal gas law we have that
Now since nRT is constant we have that
As the pressure decreased by 2 mmHg the volume becomes
B lysosgenic hhhhhjjj had to make answer longer
Answer:
its true hope this helped :)
