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3 years ago

I need to know how to solve the equations.

Chemistry

1 answer:

Sloan [31]3 years ago

7 0

Answer:

1.Therefore ethanol has : 2 mols of carbon, 1 mole of oxygen and 6 mols of hydrogen. The requested mass percents are: 52.14% ; 34.77% ; 13.15%.

2. You should get 14.007(2) which is 28.014

3. I have no idear

4.idk

5. im sorry man this is too hard

Explanation:

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Let's assume you were given 2.0 g benzil, 2.2 g dibenzyl ketone, 50 mL 95% ethanol and 0.3 g potassium hydroxide to synthesize t

almond37 [142]

Answer:

the % yield is 82%

Explanation:

Given the data in the question,

we know that;

Molar mass of benzil is 210.23 g·mol−1

Molar mass of dibenzyl ketone is 210.27 g·mol−1

Molar mass of tetraphenylcyclopentadienone is 384.5 g·mol−1

Now,

2.0 g benzil = 2 g / 210.23 g·mol−1 = 0.0095 mole

2.2 g dibenzyl ketone = 2.2 / 210.27 = 0.0105 mole

3.0 g of tetraphenylcyclopentadienone = 3 / 384.5 = 0.0078 mole

Now, the limiting reagent is benzil. 0.0095 mole can reacts wiyh 0.0095 mole of dibenzyl ketone

percentage yield = ( 0.0078 mole / 0.0095 mole ) × 100%

= 0.82 × 100%

= 82%

Therefore, the % yield is 82%

3 0

3 years ago

15. A 15.30 g sample of calcium (Ca) combines with 7.96 g of sulfur(S) to form calcium sulfide

BlackZzzverrR [31]

Answer:

17.689g

Explanation:

1: First, write out the equation you will follow:

Ca + S ⇒ CaS

2: Use the formula Mass = Mr x moles to work out the moles of both Ca and S - this will enable you to find the limiting reactant.

3: Moles Ca:

Moles = mass/ Mr = 15.3/ 40.1 = 0.382 moles.

4: Moles S:

Moles = mass/ Mr = 7.96/ 32.1 = 0.245 moles.

5: We now know S is the limiting reactant, and as there is a 1:1 ratio between S and CaS, there will also be 0.245 moles CaS.

6: Mass CaS:

Mass = Mr x moles = 72.2 x 0.245 = 17.689g

6 0

3 years ago

Which one of the following is a balanced equation?

ziro4ka [17]

Answer: OA is a balanced equation.

Explanation: For an equation to be balanced, the number of atoms and the total charge of each element in the reaction, of the product and reactant side must be the same.

Considering OA; 6 atoms of nitrogen is present in the reactant side. Shifting to the product side, 6 atoms of nitrogen is also present. Taking the other element in the reaction into account, the number of atoms of each element balances on both sides.

8 0

3 years ago

Read 2 more answers

Please this is important

ValentinkaMS [17]

Answer:

Explanation:

2C6H6 + 9O2 -> 12CO2 + 6H20

Weight of a CO2 Mol 12+ 16x2 = 44g

In 100g number of moles = 100/44= 2.2727 Moles

Number of C6H6 2moles burned when creating 12 moles of CO2

Therefore 2.2727/12 x 2 = 0.3787

3H2SO4 + 2Al(OH)3 -> Al2(SO4)3 + 6H2O

H2O weight of a 1mol is = 2+16 = 18g

2moles of Al(OH)3 cerates 6 moles of water.

3moles of sulfuric creates 6 moles of water.

5.5moles Al(OH)3 reacts with 5.5 moles of sulfuric

Therefore number of water moles = 5.5/3 x 6 = 11moles

Weight water = 11 x 18 = 198g

Cu + 2AgNO3 -> 2Ag + Cu(NO3)2

1mol of Cu produces 2moles of silver

Ag = 107.86 g/Mol

Cu = 63.54 g/Mol

In 26g Ag number of moles = (26/107.86)/2 x 63.54 = 7.658g

3K2CrO4 + 2AlPO4 -> 2K3PO4 + Al2(CrO4)3

K2CrO4 = 39x2 + 52 + 16x4 = 194g/Mol

Al2(CrO4)3 = 54 + 354 = 408g/Mol

3moles of K2CrO4 creates 1mol of Al2(CrO4)3

Therefore weight of the Al2(CrO4)3 produced by 17.5g potassium chromate

(17.5/194)/3 moles of Al2(CrO4)3 produced = 0.03moles

Al2(CrO4)3 produced = 0.03 x 408 = 12.26g

7 0

3 years ago

Nitrogen fixation is the

kenny6666 [7]

Answer:

Nitrogen fixation is the conversion of gaseous nitrogen into an organism friendly form (ammonia) .

Explanation:

Nitrogen fixation -

It is very important and necessary process by which the nitrogen gas present in the atmosphere gets converted to nitrogen derivatives like ammonia in the soil , is referred to as the process of nitrogen fixation.

This occurs due to the reason , that the derivatives of nitrogen are of much more importance than the molecular nitrogen.

Biologically the process is done by the rhizobium bacteria .

Hence ,

From the question,

The correct option is a.

5 0

3 years ago

I need to know how to solve the equations.​

I need to know how to solve the equations.