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EleoNora [17]
3 years ago
14

A car travels 2.5 hours in a Northern direction for 300km. Determine the cats speed and velocity

Chemistry
1 answer:
nika2105 [10]3 years ago
3 0

Answer:

Velocity = 120 km/h in north

Speed  =  120 km/h

Explanation:

Given data:

Distance = 300 km north

Time taken = 2.5 hr

Speed and velocity = ?

Solution:

Speed = distance / time

Speed  = 300 km / 2.5 h

Speed  =  120 km/h

Velocity = change in position / change in time

Velocity = 300 km north /  2.5 hr

Velocity = 120 km/h in north

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Explanation:

The wavelength range of Infrared radiation is 700 nanometers to 1 millimeter. This also translates to a frequency range of 430 TeraHertz  to 300 Giga Hertz.

Because the sun is a star and is hot in comparison to earth and other planetary bodies, the bigger  range of infrared radiation it emits is in the near-infrared which is mainly composed of wavelength below 4 micrometers.

The earth's surface produces infrared radiation of the mid-infrared range while cooler substances will produce far-infrared range

The thermal range of infrared ranges between wavelengths 3.5 and 2.0 micrometers and is produced by black bodies.

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3 years ago
The reaction of 2-chloropropane with sodium hydroxide can occur via both SN1 and SN2 mechanisms.
strojnjashka [21]

Answer:

Explanation:

(a) Part 1: S_N1 reaction. This is a nucleophilic substitution reaction in which we have two steps. Firstly, chlorine, a good leaving group, leaves the carbon skeleton to form a relatively stable secondary carbocation. This carbocation is then attacked by the hydroxide anion, our nucleophile, to form the final product.

To summarize, this mechanism takes places in two separate steps. The mechanism is attached below.

Part 2: S_N2 reaction. This is a nucleophilic substitution reaction in which we have one step. Our nucleophile, hydroxide, attacks the carbon and then chlorine leaves simultaneously without an intermediate carbocation being formed.

The mechanism is attached as well.

(b) The rate determining step is the slow step. Formation of the carbocation has the greatest activation energy, so this is our rate determining step for S_N1. For S_N2, we only have one step, so the rate determining step is the attack of the nucleophile and the loss of the leaving group.

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Consider four atoms from the second period: lithium, beryllium boron carbon and nitrogen which of these element has the lowest e
bearhunter [10]
Lithium has the lowest. if fluorine is the highest then lithium is the lowest. i hope this helps you out!
5 0
3 years ago
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The number of grams per mole of something is known as?​
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