The given trinagle is a right angle triangle. let the missing side be x. To find x, we would apply the pythagorean theorem which is expressed as
hypotenuse^2 = one leg^2 + other leg^2
From the triangle,
hypotenuse = 14
one leg = 9
other leg = x
Thus, we have
![\begin{gathered} 14^2=9^2+x^2 \\ 196=81+x^2 \\ x^2\text{ = 196 - 81 = 115} \\ x\text{ = }\sqrt[]{115} \\ x\text{ = 10.72} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2014%5E2%3D9%5E2%2Bx%5E2%20%5C%5C%20196%3D81%2Bx%5E2%20%5C%5C%20x%5E2%5Ctext%7B%20%3D%20196%20-%2081%20%3D%20115%7D%20%5C%5C%20x%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B115%7D%20%5C%5C%20x%5Ctext%7B%20%3D%2010.72%7D%20%5Cend%7Bgathered%7D)
To the nearest tenth, the length of the third side is 10.7
Answer: 42 pieces of gum
Step-by-step explanation: 2x+4=88
No se pero me gustaría alludar
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Answer:
x≥![\frac{7}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B6%7D)
Step-by-step explanation:
given 1.5x+3.75≥5.5
→ 1.5x≥5.5-3.75
→ 1.5x≥1.75
→ x≥![\frac{1.75}{1.5}](https://tex.z-dn.net/?f=%5Cfrac%7B1.75%7D%7B1.5%7D)
→ x≥![\frac{7}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B6%7D)