$x^3+27=0
\\x^3+3^3=0
\\(x+3)(x^2-3x+9)=0
\\x^2-3x+9=0
\\a=1,b=-3,c=9
\\
\\x_{1,2}= \frac{-b\pm \sqrt{b^2-4ac} }{2a} = \frac{-(-3)\pm \sqrt{(-3)^2-4\times1\times9} }{2\times1} =\frac{3\pm \sqrt{-27} }{2} =\frac{3\pm 3\sqrt{3}i }{2} 
\\
\\(x+3)(x-\frac{3+ 3\sqrt{3}i }{2})(x-\frac{3- 3\sqrt{3}i }{2})=0

$

4 0

3 years ago

How many solutions does the equation -3(2x+5)=-15 have?

Mamont248 [21]

Answer:

Step-by-step explanation:

-3(2x+5)=-15

-6x-15= -15

-6x=0

No solutions

4 0

2 years ago

Use the formula C= dxd

zysi [14]

Answer:

69.08m

Step-by-step explanation:

Circumference of a circle = πd where

d is the diameter of the circle

Given

diameter = 22metres

circumference of the circle = 3.14(22)

circumference of the circle = 69.08m

Hence the circumference of the circle is 69.08m

5 0

2 years ago

Read 2 more answers

Write a number sentence that will calculate a reasonable estimate for the quotient of 3325÷5​

Write a number sentence that will calculate a reasonable estimate for the quotient of 3325÷5