B It’s the one that makes sense
The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:
<span><span>x1 </span>= 0.42801</span>
<span><span>x2 </span>= −1.51414</span>
<span><span>x3 </span>= 3.08613</span>
x1 and x2 are in the desired interval [-2, 2]
f'(x) = 3x^2 - 4x - 4
so we have:
3x^2 - 4x - 4 = 0
<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6
x_1 = -4/6 = -0.66
x_ 2 = 2
According to Rolle's theorem, we have one point in between:
x1 = 0.42801 and x2 = −1.51414
where f'(x) = 0, and that is <span>x_1 = -0.66</span>
so we see that Rolle's theorem holds in our function.
The first translation picks a point and adds 4 to its x coordinate, and subtracts 10 from the y coordinate. In other words, it moves the point 4 units to the right and 10 units down.
Similarly, the second translation subtracts 1 to the x coordinate, and subtracts 9 from the y coordinate. In other words, it moves the point 1 unit to the left and 9 units down.
So, if you perform one translation after the other, you move the point 4 units to the right and 1 unit to the left along the x axis, and 10 units down and 9 more units down along the y axis.
The net result is a translation of 3 units to the right and 19 units down.
6 hope i could help good luck