Circumference of a circle is C = 2πr.
part 1)
so the radius of the smaller gear is 3 inches, so after a full rotation, namely a revolution, the smaller gear has covered an arc of 2π(3), or 6π.
what angle has the larger gear of 7 inches in radius, has it covered with an arc of 6π?
part 2)
since the larger gear has a radius of 7, in a revolution it will have an arc of 2π(7), or 14π.
now, we know the smaller gear does a 6π arc in a revolution, how many revolutions will it do in an arc of 14π?
Answer:
Y=s^2/36 and y=5.7;14.3 ft
Step-by-step explanation:
The question was not typed correctly. Here, a better version:
<em>The aspect ratio is used when calculating the aerodynamic efficiency of the wing of a plane for a standard wing area, the function A(s)=s^2/36 can be used to find the aspect ratio depending on the wingspan in feet. If one glider has an aspect ratio of 5.7, which system of equations and solution can be used to represent the wingspan of the glider? Round solution to the nearest tenth if necessary. </em>
<em>
</em>
<em>Y=s^2/36 and y=5.7;14.3 ft
</em>
<em>Y=5.7s^2 and y=36; s=2.5ft
</em>
<em>Y=36s^2 and y=0; s=0.4 ft
</em>
<em>Y=s^2/36 +5.7 and y=0; s=5.5 ft</em>
In the function A(s)=s^2/36 A(s) represents the aspect ratio and s the wingspan. If one glider has an aspect ratio of 5.7, then A(s) = 5.7. We want to know the wingspan of the glider. Replacing A(s) by Y we get the following system of equation:
Y=s^2/36
with y = 5.7
5.7 = s^2/36
5.7*36 = s^2
√205.2 = s
14.3 ft
X - number of months ( 1, 2 or 3 );
A function is:
f ( x ) = 50 x + 200
A reasonable domain is:
x ∈ { 1, 2, 3 }
The range is:
y ∈{ $250, $300, $350 }
We have been given that a sphere and a cylinder have the same radius and height. The volume of the cylinder is 21 meters cubed. We are asked to find the volume of the sphere.
We know that height of sphere is equal to its radius. This means that .
Using , we will get:
Upon comparing volume of sphere and volume of cylinder, we can see that volume of sphere is times volume of cylinder.
Therefore, the volume of the sphere would be 28 cubic meters.
Tan = opp/adj
Tan A = 16/12