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Lena [83]
2 years ago
11

Choose the expression which represents the simplest form of (-4x2)

Mathematics
1 answer:
Lelechka [254]2 years ago
7 0

Answer:

Step-by-step explanation:

No idea

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Dan thinks of a number
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Answer:

-1

Step-by-step explanation:

2 - 3 = -1

5 0
2 years ago
Which expression is equivalent to is m<4
Tju [1.3M]

Answer:

(g*h)=x.

Step-by-step explanation:

the expression is equivalent

7 0
2 years ago
3. Write the equation of a line that is perpendicular to the given line and that passes through the given point.
prohojiy [21]
To find the perpendicular line a y- 2 = 7/3 (x + 5) you must first observe that the slope is m = 7/3, therefore, the slope of the perpendicular line put of the reciprocal, that is, m = - 3/7. So the possible options are A or C, but since the point (-4, 9) must go through the line, we find that the equation that satisfies that is option C.Therefore the perpendicular line that passes through the point (-4, 9) is C. y - 9 = -3/7 (x + 4)
3 0
3 years ago
Two​ shooters, Rodney and​ Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark
Sedaia [141]

Complete Question

Answer:

a

  SE  = 0.66}

b

-3.29 <  \mu_1 - \mu_2 <  -0.70  

Step-by-step explanation:

From the question we are told that

  The sample size is  n  = 60

   The first sample mean is  \= x _1  =  8

    The second sample mean is   \= x _2  =  10

    The first variance is  v_1 =  0.25

    The first variance is  v_2 =  0.55

Given that  the confidence level is 95% then the level of significance is 5% =  0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the first standard deviation is  

     \sigma_1 =  \sqrt{v_1}

=>   \sigma_1 =  \sqrt{0.25}

=>   \sigma_1 =  0.5

Generally the second standard deviation is

     \sigma_2 =  \sqrt{v_2}

=>   \sigma_2 =  \sqrt{0.55}

=>   \sigma_2 =  0.742    

Generally the first standard error is

     SE_1  =  \frac{\sigma_1}{\sqrt{n} }

      SE_1  =  \frac{0.5}{\sqrt{60} }

     SE_1  =  0.06

Generally the second standard error is

     SE_2  =  \frac{\sigma_2}{\sqrt{n} }

      SE_2  =  \frac{0.742}{\sqrt{60} }

     SE_2  =  0.09

Generally the standard error of the difference between their mean scores is mathematically represented as    

      SE  =  \sqrt{SE_1^2 + SE_2^2 }

=>     SE  =  \sqrt{0.06^2 +0.09^2 }

=>     SE  = 0.66}

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } *  SE) <  \mu_1 - \mu_2 <  (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } *  SE)

=> (8 -10) -(1.96 *  0.66) <  \mu_1 - \mu_2 <  (8-10) +(Z_{\frac{\alpha }{2} } *  0.66)  

=>  -3.29 <  \mu_1 - \mu_2 <  -0.70  

 

5 0
3 years ago
X - 5y = 10; (0, -2) Group of answer choices no yes
mr Goodwill [35]
  • Yes, this linear equation is correct on point (0,-2).

Given that:

  • The linear equation

         x - 5y = 10;

  • The point

        (0, -2)

To find

  • We have to prove LHS = RHS

So, according to the question

We have,

The linear equation,

         x - 5y = 10; and point is (0,-2)

From equation,

         x - 5y = 10

Take the left part of given linear equation,

         LHS = x - 5y

Now, putting the values, x = 0 and y = -2.

Then, we will be get.

                = x - 5y

                = (0) - 5 ×(-2)

                = - 5 × -2

                = 10.

So, we can say that

          LHS = RHS.

Where,

           LHS = Left Hand Side.

           RHS =  Right Hand Side.      

We can solve that linear equation in other way,

When we put x = 0, we get y = -2.

So, if we put x = 1, we get y = -9/5.

Similarly, if x = 2, then y = -8/5.

Now, we can say that points (0,-2), (1,-9/5) and (2,-8/5) are lie in the linear equation x - 5y = 10.

To learn more about linear equation, please click on the link;

brainly.com/question/13738061

#SPJ1

6 0
1 year ago
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