Choose the expression which represents the simplest form of (-4x2)

Dan thinks of a number

puteri [66]

Answer:

-1

Step-by-step explanation:

2 - 3 = -1

5 0

2 years ago

Which expression is equivalent to is m<4

Tju [1.3M]

Answer:

(g*h)=x.

Step-by-step explanation:

the expression is equivalent

7 0

2 years ago

3. Write the equation of a line that is perpendicular to the given line and that passes through the given point.

prohojiy [21]

To find the perpendicular line a y- 2 = 7/3 (x + 5) you must first observe that the slope is m = 7/3, therefore, the slope of the perpendicular line put of the reciprocal, that is, m = - 3/7. So the possible options are A or C, but since the point (-4, 9) must go through the line, we find that the equation that satisfies that is option C.Therefore the perpendicular line that passes through the point (-4, 9) is C. y - 9 = -3/7 (x + 4)

3 0

3 years ago

Two shooters, Rodney and Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark

Sedaia [141]

Complete Question

Answer:

a

$SE = 0.66}$

b

$-3.29 < \mu_1 - \mu_2 < -0.70$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The first sample mean is $\= x _1 = 8$

The second sample mean is $\= x _2 = 10$

The first variance is $v_1 = 0.25$

The first variance is $v_2 = 0.55$

Given that the confidence level is 95% then the level of significance is 5% = 0.05

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the first standard deviation is

$\sigma_1 = \sqrt{v_1}$

=> $\sigma_1 = \sqrt{0.25}$

=> $\sigma_1 = 0.5$

Generally the second standard deviation is

$\sigma_2 = \sqrt{v_2}$

=> $\sigma_2 = \sqrt{0.55}$

=> $\sigma_2 = 0.742$

Generally the first standard error is

$SE_1 = \frac{\sigma_1}{\sqrt{n} }$

$SE_1 = \frac{0.5}{\sqrt{60} }$

$SE_1 = 0.06$

Generally the second standard error is

$SE_2 = \frac{\sigma_2}{\sqrt{n} }$

$SE_2 = \frac{0.742}{\sqrt{60} }$

$SE_2 = 0.09$

Generally the standard error of the difference between their mean scores is mathematically represented as

$SE = \sqrt{SE_1^2 + SE_2^2 }$

=> $SE = \sqrt{0.06^2 +0.09^2 }$

=> $SE = 0.66}$

Generally 95% confidence interval is mathematically represented as

$(\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } * SE) < \mu_1 - \mu_2 < (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } * SE)$

=> $(8 -10) -(1.96 * 0.66) < \mu_1 - \mu_2 < (8-10) +(Z_{\frac{\alpha }{2} } * 0.66)$

=> $-3.29 < \mu_1 - \mu_2 < -0.70$

5 0

3 years ago

X - 5y = 10; (0, -2) Group of answer choices no yes

mr Goodwill [35]

Yes, this linear equation is correct on point (0,-2).

Given that:

The linear equation

x - 5y = 10;

The point

(0, -2)

To find

We have to prove LHS = RHS

So, according to the question

We have,

The linear equation,

x - 5y = 10; and point is (0,-2)

From equation,

x - 5y = 10

Take the left part of given linear equation,

LHS = x - 5y

Now, putting the values, x = 0 and y = -2.

Then, we will be get.

= x - 5y

= (0) - 5 ×(-2)

= - 5 × -2

= 10.

So, we can say that

LHS = RHS.

Where,

LHS = Left Hand Side.

RHS = Right Hand Side.

We can solve that linear equation in other way,

When we put x = 0, we get y = -2.

So, if we put x = 1, we get y = -9/5.

Similarly, if x = 2, then y = -8/5.

Now, we can say that points (0,-2), (1,-9/5) and (2,-8/5) are lie in the linear equation x - 5y = 10.

To learn more about linear equation, please click on the link;

brainly.com/question/13738061

#SPJ1

6 0

1 year ago