Because this is a second degree equation you will have 2 solutions. When you take the square root of a number you have to account for both the positive and negative roots. Since the square root of 289 is 17 then your solutions are +17 and -17.
Answer:
D
Step-by-step explanation:

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Factor out 2 on the numerator and 2x on the denominator.
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Cancel the factor (x + 2) on the numerator/ denominator
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← cancel the 2 on numerator/ denominator
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: x ≠ 0