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luda_lava [24]
3 years ago
9

Carla wants to know how many students in her school enjoy watching reality TV shows. She asks all 22 students in her science cla

ss and finds that 40% of her classmates enjoy watching reality TV shows. She claims that 40% of the school's student population would be expected to enjoy watching reality TV shows. Is Carla making a valid inference about her population? No, it is not a valid inference because she asked all 22 students in her science class instead of taking a sample from her music class No, it is not a valid inference because she asked all 22 students in her science class instead of taking a sample of the students in her school Yes, it is a valid inference because she asked all 22 students in her science class Yes, it is a valid inference because her classmates make up a random sample of the students in the school
Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0
Statistic significance requires that your sample be representative of the population, but I'm struggling with this because if the class is an elective then the answer would be: <span>No, it is not a valid inference because she asked all 22 students in her science class instead of taking a sample of the students in her school.
BUT if the class is required, as most science classes are, then it WOULD be a random sample of the school. So the last option would be correct. 

My guess though is that the teacher is looking for answer B.
</span>
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Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]

Given that

\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]

Let:

<em />L \to<em> Letters</em>

<em />C \to<em> Cost</em>

<em />

Using proportional reasoning, we have:

C  = kL

Where

<em />k \to<em> ratio of proportion</em>

For the first values of C and L, we have:

C  = kL

0.45 = k \times 10

Divide both sides by 10

k = 0.045

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C = 0.045L

<u>When C = 6.75, we have:</u>

C = 0.045L

6.75 = 0.045L

Solve for L

L = \frac{6.75}{0.045}

L = 150

<u>When L = 7, we have:</u>

C = 0.045L

C = 0.045 \times 7

C = 0.315

<u>When L = 1, we have:</u>

C = 0.045L

C = 0.045 \times 1

C = 0.045

<u>When L = 500, we have:</u>

C =0.045L\\

C =0.045 \times 500

C =22.5

<u>When C = 18.90, we have:</u>

C = 0.045L

18.90 = 0.045L

Solve for L

L=\frac{18.90}{0.045}

L=420

Hence, the complete table is:

\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]

Read more about proportions at:

brainly.com/question/21126582

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What is 0.644 in expanded form
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I hope this helps you


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Let a and b be positive integers. 23^a x 23^b
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3 years ago
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