Answer:
A.) 39.5 m
B.) 0
C.) 60m/s^2
Explanation:
Given that a displacement function of a particle is x(t)=(20t^2-15t+200).
To Find the total displacement,
Reduce everything by dividing them by 5
X(t) = 4t^2 - 3t + 40 ...... (1)
For instantaneous velocity, differentiate x(t). That is,
dy/dt = 60t - 15 ...... (2)
But dy/dt = velocity.
If dy/dt = 0, then
60t - 15 = 0
60t = 15
t = 15/60
t = 0.25s
Substitutes t in equation (1)
Total displacement will be
X(t) = 4(0.25)^2 - 3(0.25) + 40
X(t) = 0.25 - 0.75 + 40
Total displacement = 39.5 m
To calculate instantaneous velocity, substitute t into equation (2)
V = 60 (0.25) - 15
V = 0.
and to find instantaneous acceleration, differentiate dv/dt
dv/dt = 60
Therefore, acceleration = 60 m/s^2
True, because it is the state between solid and liquid
The angle through which the grinding wheel rotates in the first second = <u>5300 rad</u>
Angular velocity is, the time charge at which an object rotates, or revolves, about an axis, or at which the angular displacement between our bodies changes. within the discern, this displacement is represented via the angle θ among a line on one body and a line on the alternative.
The angular velocity is described as the charge of trade of the angular position of a rotating body. Linear speed is defined because the charge of change of displacement with respect to time whilst the item moves alongside a straight course.
Initial angular velocity of the grinding wheel = ω1 = 5500 rad/s
Final angular velocity of the grinding wheel = ω2 = 0 rad/s (Comes to rest)
Time is taken by the grinding wheel to come to rest = T = 10 sec
Angular acceleration of the grinding wheel = α
2 = ω1 + αT
0 = 5500 + α(10)
α = - 400 rad/s2
Negative as it is deceleration.
The angle through which the grinding wheel rotates in the first second = θ
Time period = T1 = 1 sec
θ = ω₁T1 + αT1²/2
θ = (5500)(1) + (-400)(1)²/2
θ = 5300 rad
The angle through which the grinding wheel rotates in the first second = <u>5300 rad</u>
Learn more about angular velocity here:-brainly.com/question/6860269
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Answer:
An accelerometer is a tool that measures proper acceleration.[1] Proper acceleration is the acceleration (the rate of change of velocity) of a body in its own instantaneous rest frame;[2] this is different from coordinate acceleration, which is acceleration in a fixed coordinate system. For example, an accelerometer at rest on the surface of the Earth will measure an acceleration due to Earth's gravity, straight upwards[3] (by definition) of g ≈ 9.81 m/s2. By contrast, accelerometers in free fall (falling toward the center of the Earth at a rate of about 9.81 m/s2) will measure zero.
Accelerometers have many uses in industry and science. Highly sensitive accelerometers are used in inertial navigation systems for aircraft and missiles. Vibration in rotating machines is monitored by accelerometers. They are used in tablet computers and digital cameras so that images on screens are always displayed upright. In unmanned aerial vehicles, accelerometers help to stabilise flight.
When two or more accelerometers are coordinated with one another, they can measure differences in proper acceleration, particularly gravity, over their separation in space—that is, the gradient of the gravitational field. Gravity gradiometry is useful because absolute gravity is a weak effect and depends on the local density of the Earth, which is quite variable.
Single- and multi-axis accelerometers can detect both the magnitude and the direction of the proper acceleration, as a vector quantity, and can be used to sense orientation (because the direction of weight changes), coordinate acceleration, vibration, shock, and falling in a resistive medium (a case in which the proper acceleration changes, increasing from zero). Micromachined microelectromechanical systems (MEMS) accelerometers are increasingly present in portable electronic devices and video-game controllers, to detect changes in the positions of these devices.
Explanation:
hope this helps !!!!
