An object is traveling with a constant velocity of 5 m/s. How far will it have gone after 7 s?
1 answer:
You might be interested in
Answer:
a)<em> 2000 W/m² </em><em>; </em>b) 636.94 W/m<em>².sr ; </em><em>c) </em>0.5
Explanation:
a)
The formula for calculation of total emissive power is:
Total emissive power = E = E'<em>λdλ</em>
<em> </em>= (0)d<em>λ + </em>
(100)d<em>λ + </em>
(200)d<em>λ + </em>
(100)d<em>λ </em>
(0)d<em>λ</em>
<em>where a = 5; b = 10; c = 15; d = 20; e = 25</em>
<em> = 0 +100(10-5) + 200(15-10) +100(20-15) + 0</em>
<em> = 2000 W/m²</em>
b)
The formula for total intensity of radiation is:
I = E/π = 200/3.14 = 636.94 W/m<em>².sr </em>
<em>c)</em>
Fo submissive power leaving the surface in range π/4 ≤θ≤π/2
[E(π/4 ≤θ≤π/2)]/E = Icosθsinθ dθdΦdλ
where f = infinity, g=2π, h=π/4, i=π/2
By simplifying, we get
= (-1/2)[cos(2π/2)-cos(2π/2)]
= -0.5(-1-0)
=0.5