Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Answer:
Step-by-step explanation:
<h3>Given</h3>
- m∠DXB = 70° 15' 12''
- m∠DXC = 30° 30' 20''
<h3>To find</h3>
<h3>Solution</h3>
<u>According to Angle Addition postulate:</u>
<u>Therefore</u>
- m∠CXB = m∠DXB - m∠DXC
- m∠CXB = 70° 15' 12''- 30° 30' 20'' = 39° 44' 52''
The answer is a scalene triangle
The correct answers would be both B. and D.
A, and C are incorrect because they say that you would be putting 6 items total into each bag when it multiplies 2 and 3 together when there are only 5 items being put into each, which is what B and D is showing which is why those are the correct answers.
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Answer:
-5 is the slope and -16 is the y intercept