The answer should be on Photomath
Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem
t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).
So t = √(3r^2) = √3r answer.
What we want to do first is isolate the variable. To do this we need to multiply each side by 5 to remove the fraction
5 * 5 = 5*

w
Simplify the right side
5 *

w = 1w
Now simplify the left side
5 * 5 = 25
Then we get...
25 = w
There's your answer!
Answer:
The answer is -9,9 Its funny cuz I just did this problem on Khan academy
Step-by-step explanation:
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