The distance between planets in two stellar systems is 1.6x10^6 miles. If a spaceship is able to travel at 8,400 miles per hour,
1 answer:
Answer:
Yes it will be able to make the journey in under a year.
Step-by-step explanation:
To find out how many hours it will take and divide by 8400
So it will take the space ship 190.476 hours to make the trip.
Next, ask our self, how many hours are in a year?
To find out multiply 365 * 24 = 8760 hr
The 365 = number of day in a year. The 24 = number of hours in a day.
Knowing how many hours there are in a year and how long the trip will take tells us that the journey can be made under a year since there are 8760 hours in a year and we know we can make it there in 190.476 hr traveling at 8400 mph
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Let p be the proportion. Let c be the given confidence level , n be the sample size.
Given: p=0.3, n=1180, c=0.99
The formula to find the Margin of error is
ME =
Where z (α/2) is critical value of z.
P(Z < z) = α/2
where α/2 = (1- 0.99) /2 = 0.005
P(Z < z) = 0.005
So in z score table look for probability exactly or close to 0.005 . There is no exact 0.005 probability value in z score table. However there two close values 0.0051 and 0.0049 . It means our required 0.005 value lies between these two probability values.
The z score corresponding to 0.0051 is -2.57 and 0.0049 is -2.58. So the required z score will be average of -2.57 and -2.58
(-2.57) + (-2.58) = -5.15
-5.15/2 = -2.575
For computing margin of error consider positive z score value which is 2.575
The margin of error will be
ME =
=
= 2.575 * 0.0133
ME = 0.0342
The margin of error is 0.0342
