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4 years ago

What is the mean proportion between 10 and 40?

Mathematics

1 answer:

lozanna [386]4 years ago

6 0

Answer:

Step-by-step explanation:

10, 20, 30, 40

Answer:25

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Define fn : [0,1] --> R by the

sasho [114]

Answer:

The sequence of functions $\{x^{n}\}_{n\in \mathbb{N}}$ converges to the function

$f(x)=\begin{cases}0&0\leq x$ .

Step-by-step explanation:

The limit $\lim_{n\to \infty }c^{n}$ exists and converges to zero whenever $\lvert c \rvert$ . But, if $c=1$ the sequence $\{c^{n}\}$ is constant and all its terms are equal to $1$ , then converges to $1$ . Using this result, consider the sequence of functions $\{f_{n}\}$ defined on the interval $[0,1]$ by $f_{n}(x)=x^{n}$ . Then, for all $0\leq x$ we have that $\lim_{n\to \infty}x^{n}=0$ . Now, if $x=1$ , then $\lim_{n\to \infty }x^{n}=1$ . Therefore, the limit function of the sequence of functions is

$f(x)=\begin{cases}0&0\leq x$ .

To show that the convergence is not uniform consider $0$ . For any $n>1$ choose $x\in (0,1)$ such that $\varepsilon^{1/n}$ . Then

$\varepsilon$

This implies that the convergence is not uniform.

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3 years ago

The figure shows triangle ABC with medians AF, BD, and CE. Segment AF is extended to H in such a way that segment GH is congruen

attashe74 [19]

Answer: Segment GD is parallel to segment HC.

Step-by-step explanation:

In ΔAHC

AG=GH (given)...........1

As BD is the median of ΔABC bisecting AC at D

∴AD=DC.........2

⇒ $\frac{AD}{DC}=\frac{AG}{GH}=1$ (from 1 and 2)

⇒segment GD is dividing the sides AH and AC in same ratio.

Therefore by the converse of Basic proportionality theorem,segment GD is parallel to segment HC.

Converse of basic probability theorem states that if a line divides any two sides of a triangle in the same ratio, then the line must be parallel to the third side.

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3 years ago

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