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3 years ago

How do you find the height of a trapezoid

Mathematics

2 answers:

9966 [12]3 years ago

6 0

<span>To solve this question, you must divide the trapezoid into a rectangle and two right triangles. Using the Pythagorean Theorem, you would calculate the height of the triangle which is 4. The dimensions of the rectangle are 5 and 4, hence the area will be 20.</span>

dem82 [27]3 years ago

4 0

You can find the height of a trapezoid by dropping the altitude and using the side of the triangle that you have to find the height using the 45-45-90 triangle method or 30-60-90 triangle method, which will give you the other two sides, including the height

Hopefully that makes sense

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The first term of a geometric sequence is 8 and the fourth term is 216. What is the sum of the first 12 terms of the correspondi

Leokris [45]

Answer:

2,125,760

Step-by-step explanation:

The first term (a) is 8

The fourth term is 216

Hence the sum of the first 12 term can be calculated as follows

= 8-8(3)^12/1-3

= 8-24^12/-2

= 2,125,760

The sum of first 12 terms is 2,125,760

4 0

3 years ago

BHJGHJWvhjwvhjdvgjdvgwv

sveta [45]

Answer:

................Uhm not a question.....................................................o/o

3 0

2 years ago

Can Someone tell me how to find a rate of change and an initial value

kow [346]

Depends on which rate of change you're talking about. The rate of change is another term for a slope of a function. There's two(2) different version of rate of change.

First version one is the instantaneous rate of change. aka derivative. This one is found simply by taking the derivative of a function.

Second version is the average rate of change, which is found using the slope formula, (y₂ - y₁)/(x₂ - x₁)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Initial value problem should give you an initial point (x, y) to plug into your function. You plug those x,y value in to find your answer.

There's variation of initial value problems so I can't give you any specific details on how to do it unless you can post the question.

8 0

2 years ago

Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The cumulative distribution for this function is given by:

$F(X) = 1- e^{-\lambda x}, x\ geq 0$

We know the value for the mean on this case we have that :

$mean = \frac{1}{\lambda}$

$\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367$

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: $Var(X) =\frac{1}{\lambda^2}$

And the deviation would be:

$Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725$

And the mean is given by $Mean = 2.725$

Two deviations correspond to 5.540, so we want this probability:

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

$P(X$

8 0

3 years ago

Complete the explanation of the procedure that can be used to solve 5[3(x + 4) − 2(1 − x)] − x − 15 = 14x + 55. Then solve the e

Debora [2.8K]

Answer:

x = 2.

Step-by-step explanation:

5[3(x + 4) − 2(1 − x)] − x − 15 = 14x + 55

5[3x + 12 - 2 + 2x] - x - 15 = 14x + 55

5[5x + 10] - x - 15 = 14x + 55

25x + 50 - x - 15 = 14x + 55 Now we subtract 14x from both sides:

25x + 50 - x - 15 - 14x = 14x - 14x + 55

10x + 50 - 15 = 55 Now we subtract 50, add 15 to both sides:

10x + 50 - 50 - 15 + 15 = 55 - 50 + 15

10x = 20

x = 2.

8 0

2 years ago