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tatyana61 [14]
3 years ago
13

I need help please help me ​

Mathematics
1 answer:
dem82 [27]3 years ago
6 0

Answer:

Option A is the answer

mark me as brainliest

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If X = 4 units, Y = 3 units, and Z = 6 units, then what is the surface area of the right triangular pyramid shown above?
zepelin [54]

Answer:

C. 42

Step-by-step explanation:

<em>Since the triangle making up the base of the right triangular pyramid is equilateral, the three lateral triangles will have equal areas. To find the surface area of the pyramid, find the area of one of the lateral triangles and multiply it by 3. Then, add that to the area of the triangle that forms the base.</em>

<em>Area of Lateral Triangle = 1/2 · base · height</em>

<em>                                        = 1/2 · X · Z</em>

<em>                                       = 1/2 ·  4 units ·  6 units</em>

<em>                                       = 12 square units</em>

<em>Area of Base Triangle = 1/2 ·  base ·  height</em>

<em>                                     = 1/2 ·  X ·  Y</em>

<em>                                     = 1/2 ·  4 units ·  3 units</em>

<em>                                    = 6 square units</em>

<em>Now, use the method described above to find the surface area of the pyramid.</em>

<em>Surface Area = 3( Area lateral ) + ( Area base )</em>

<em>                      = 3 ( 12 square units ) + ( 6 square units )</em>

<em>                     = 42 square units</em>

6 0
3 years ago
Which statements are appropriate to use in an online academic environment? Check all that apply.
Pavel [41]

Answer:

1,3, and 7th option.

Step-by-step explanation:

<em> I just did the questions.</em>

<em>Add me on instagram sheluvsayden</em>

<em />

7 0
3 years ago
Aubreys dinner cost $85 she tips the waitstaff 30% for excellent service
Pavel [41]

Answer:

25.5

Step-by-step explanation:

4 0
3 years ago
Please help math question WILL MARK AS BRAINLIEST IF CAN PLEASE HELP!!
alukav5142 [94]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth
taurus [48]

Answer:

So, solution of  the differential equation is

y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\

It is a homogeneous solution:

y_h(t)=c_1e^{-2i t}+c_2e^{2i t}

Now, we finding a particular solution.

y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\

we get

y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

So, solution of  the differential equation is

y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

7 0
3 years ago
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