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lord [1]
3 years ago
14

What’s the correct answer for this question?

Mathematics
1 answer:
Serggg [28]3 years ago
8 0

Answer:

8.

Step-by-step explanation:

A dilation means that the initial value is being <u>multiplied</u> by the value of the scale factor.

Therefore, to solve this, you would proceed with:

10×\frac{4}{5} = 8.

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What is the common ratio? {250, 50, 10, 2...}
Allisa [31]

Answer:

5

Step-by-step explanation:

The common ration can be found by dividing the 2nd number from the 1st number:

250 / 50

which equals 5

250 / 50 = 5

         you can do this by any number, for example:

         50 / 10 =5

         10 / 2 = 5

6 0
3 years ago
Fifty multiplied by the quantity twenty divided by a number n is greater than or equal to two hundred fifty
Fudgin [204]
4 is the correct answer
8 0
3 years ago
Please can I have some help thank you :)
Evgen [1.6K]

9514 1404 393

Answer:

  £592 for 16 boxes

Step-by-step explanation:

The classroom floor area is ...

  A = LW = (8.8 m)(2.2 m) = 19.36 m²

The cupboard floor area is ...

  A = (2.3 m)(2.1 m) = 4.83 m²

Then the total area to be covered is ...

  19.36 m² +4.83 m² = 24.19 m²

At 1.6 m² per box, the number of boxes required is ...

  (24.19 m²)/(1.6 m²/box) = 15.12 boxes

If we assume we can only purchase whole boxes, we need to purchase 16 boxes to cover the floor. The cost will be ...

  (16 boxes)(£37/box) = £592 . . . . cost of laminate to replace the floor

8 0
3 years ago
Need help with this question
svlad2 [7]
I cant see it, your camera isn't focused on the picture.
6 0
3 years ago
A 2000 kg car, initially at rest, is accelerated along a horizontal roadway at 3 m/s2. What is the average power required to bri
FromTheMoon [43]

Answer:

Power = 120000 watts

Step-by-step explanation:

mass = 2000kg

acceleration = 3m/s²

velocity = 20m/s

Force = mass x acceleration

Force = 2000 x 3 = 6000 Newton

Power = Force x velocity

Power = 6000 x 20 = 120000 watts

Since 1000 watts = 1kilo-watts

Power = 120000 watts or 120 kilo-watts

5 0
3 years ago
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