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2 years ago

(Please help me quickly! Timed quiz) Find the range of the function. (Picture below)

Mathematics

1 answer:

Ostrovityanka [42]2 years ago

4 0

Answer:

=/ this means that the equation isn't equal

1-x^2 =/ 0

1 =/ x^2

x =/ +1

x =/ -1

then the answer will be B

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1. A researcher believes that university students weigh more than the population. The researcher reasons that more time spent on

andrew11 [14]

Answer:

The null and alternative hypotheses are:

$H_{0}: \mu = 170$

$H_{a}: \mu >170$

Under the null hypothesis, the test statistic is:

$z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}} }$

$=\frac{180-170}{\frac{35}{\sqrt{225}} }$

$=\frac{10}{2.33}$

$=4.29$

Now, we have to find the right tailed z critical value at 0.10 significance level. Using the standard normal table, we have:

$z_{critical} = 1.28$

Since the test statistic is greater than the z critical value, we therefore, reject the null hypothesis and conclude that there is sufficient evidence to support the claim that the university students weigh more than the population.

8 0

3 years ago

Marc can afford a $750 monthly mortgage payment. If the current mortgage rates are 5% and he wishes to have a 30-year mortgage,

Svetllana [295]

$136,280 would be how much he can borrow.

6 0

3 years ago

Read 2 more answers

Challenge fr y'all. solve this to get 50 points and brainliest coming up if you get the right answer

TEA [102]

Answer:

See below

Step-by-step explanation:

Use the law of cosines:

$AB=\sqrt{PA^2+PB^2-2*PA*PB*cosP}$
$AB=\sqrt{60^2+100^2-2*60*100*cos80} =\sqrt{11516.22} =107.31$

ii)

Use the law of sines:

sin ∠A / PB = sin ∠P / AB
sin ∠A / 100 = sin 80 / 107.31
sin ∠A = 100 sin 80 deg / 107.31
sin ∠A = 0.92
∠A = arcsin 0.92
∠A = 67° (rounded)

iii)

Bearing of B from A:

90° + (67° - 30°) =
127°

PB is longer distance. Time to reach B:

t = d/s
t = 100/20 = 5 hours

The speed s of the slower ship:

s = d/t
s = 60/5 = 12 km/h

3 0

2 years ago

Read 2 more answers

1. Find the area of the composite figure to the nearest hundredth.

Leto [7]

Answer:

#1: 751.56 mm²

#2: 477 km²

Step-by-step explanation:

First I noted the semicircle on the left, which has a radius of 12.5 mm. The formula for finding the area of a semicircle is 1/2(πr²).

1/2(3.14 * (12.5)²)

12.5 squared is 156.25.

1/2(3.14 * 156.25)

Multiply 3.14 by 156.25 to get 490.625.

1/2(490.625)

Divide 490.625 by 2 to get 245.3125.

245.3125 mm² for the semicircle

Then, I split the rest of into a 12.5 by 25 rectangle and a 31 by 12.5 triangle.

(12.5 * 25) + 1/2(31 * 12.5)

Multiply 12.5 by 25 to get 312.5.

312.5 + 1/2(31 * 12.5)

Multiply 31 by 12.5 to get 387.5.

312.5 + 1/2(387.5)

Multiply 1/2 by 387.5 to get 193.75

312.5 + 193.75

Add 312.5 and 193.75 to get 506.25.

506.25 mm² for the rest of the figure.

Now add the two measures, and you have your answer for #1.

245.3125 + 506.25 = 751.5625 mm², which rounds to 751.56 mm².

The area of the composite figure is 751.56 mm².

Now for #2. First, find the area of the triangle.

1/2(40 * 27)

Multiply 40 by 27 to get 1080.

1/2(1080)

Multiply 1/2 by 1080.

590 km² for the triangle.

Now find the area of the circle.

3.14 * 6²

3.14 * 36

113.04 km² for the circle.

Now subtract the area of the circle from the area of the triangle.

590 - 113.04

476.96 km², which rounds to 477.0 km².

The area of the shaded region is 477 km².

6 0

3 years ago

Read 2 more answers

Help please?!

Furkat [3]

Well from what i know here's what i would put........
-4 * -2 = 8 - 2 = 6
-4 * -1 = 4 - 2 = 2
-4 * 0 = 0 - 2 = -2
so it does represent a function......I really hope that helped!!

8 0

3 years ago