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3 years ago

Find the slope of the line through (6,2) and(4 -2)

Mathematics

1 answer:

mestny [16]3 years ago

7 0

The slope to your equation is
x=2

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A rectangular box is to have a square base and a volume of 20 ft3. If the material for the base costs $0.30 per square foot, the

fomenos

Answer:

Step-by-step explanation:

Im sorry i dont really know ur anwer. Hope someone else can help you.

8 0

3 years ago

need help asap need help asap need help asap need help asap need help asap need help asap need help asap need help asap need hel

romanna [79]

Answer:

yes? what do you need help with

Step-by-step explanation:

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2 years ago

Demerol 45mg and atropine 400mcg/ml give how much per ml to total volume to inject demerol contains 50mg/ml, atropine contains 4

OverLord2011 [107]

Answer:

Volume injected = 1.65 ml

Step-by-step explanation:

mass of Demerol =45 mg.

density of pre-filled in syringe = 50 mg/ml

Volume = 45/50 = 0.9 ml

For atropine mass = 0.3 mg

density= 400 mcg/ml [ Note : 1 mcg = 0.001 mg]

volume filled = 0.3/400(0.001) = 0.75 ml

So, the total volume filled = 0.75+0.9 = 1.65 ml

6 0

3 years ago

Plz help me i have to have this done by 5pm today

katen-ka-za [31]

Answer:

C it wasnt hard

Step-by-step explanation:

6 0

3 years ago

After a college football team once again lost a game to their archrival, the alumni association conducted a survey to see if alu

valentina_108 [34]

Answer:

P-value for this hypothesis test is 0.00175.

Step-by-step explanation:

We are given that the alumni association conducted a survey to see if alumni were in favor of firing the coach.

A simple random sample of 100 alumni from the population of all living alumni was taken. Sixty-four of the alumni in the sample were in favor of firing the coach.

Let p = proportion of all living alumni who favored firing the coach

SO, Null Hypothesis, $H_0$ : p = 0.50 {means that the majority of alumni are not in favor of firing the coach}

Alternate Hypothesis, $H_A$ : p > 0.50 {means that the majority of alumni are in favor of firing the coach}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of the alumni in the sample who were in favor of firing the coach = $\frac{64}{100}$ = 0.64

n = sample of alumni = 100

So, test statistics = $\frac{0.64-0.50}{{\sqrt{\frac{0.64(1-0.64)}{100} } } } }$

= 2.92

Now, P-value of the hypothesis test is given by ;

P-value = P(Z > 2.92) = 1 - P(Z $\leq$ 2.92)

= 1 - 0.99825 = 0.00175

Therefore, the P-value for this hypothesis test is 0.00175.

4 0

3 years ago