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solmaris [256]
3 years ago
8

Pls help or i will fail

Mathematics
1 answer:
Finger [1]3 years ago
8 0
Seems like you’re gonna fail
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,,,,,??,??,,,,,,,,,,,,,,,,
Andre45 [30]

Answer:

  the one real zero is in the interval (-1, 0)

Step-by-step explanation:

Descartes' rule of signs tells you there are 0 or 2 positive real zeros. Changing the signs of the odd-degree terms and applying that rule again tells you there is one negative real zero. At the same time, those coefficients (-3, -5, -5, +7) have a negative sum, so you know ...

  f(-1) = -6

  f(0) = +7

so there is a zero in the interval (-1, 0).

__

You can try a few values between x=0 and x=10 to see what the function does in that part of the graph. You find ...

  f(1) = 10

  f(2) = 21

  f(3) = 58

So, it is safe to conclude that there are no real zeros for x > 0.

The only real zero of f(x) is in the interval (-1, 0).

_____

I like to use a graphing calculator for problems like this.

7 0
3 years ago
Find ten rational numbers between -2/5 and 1/2
Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

-1/5

-1/7

-1/8

-1/9

-1/10

0

1/6

1/5

1/4

1/3

8 0
3 years ago
Consider the function f(x) = x² – 3x – 4 and complete parts (a) through (C). (a) Find f(a+h); f(a+h)-f(a) (b) Find (c) Find the
Artist 52 [7]

Answer:

(a)

f(a+h)=a^{2} +2ah+h^{2} -3a-3h-4

(b)

f(a+h)-f(a)=2ah+h^{2} -3h

(c)

\frac{df(a+h)}{dx} \left \{ { \atop {a=7}} \right. =2h+11

Step-by-step explanation:

(a)

Simply evaluate (a+h) in the function:

f(a+h)=(a+h)^{2} -3(a+h)-4=a^{2} +2ah+h^{2} -3a-3h-4

(b)

Evaluate (a) in the function:

f(a)=a^{2} -3a-4

Using the previous answers lets calculate f(a+h)-f(a)

f(a+h)-f(a)=a^{2} +2ah+h^{2} -3a-3h-4-(a^{2} -3a-4)=2ah+h^{2} -3h

(c) To find the rate of change of f(a+1) when a=7 we need to calculate its derivate at that point:

\frac{df(a+h)}{dx} \left \{ { \atop {a=7}} \right. =2a+2h-3=2(7)+2h-3=2h+14-3=2h+11

7 0
3 years ago
Carrie will spin a spinner 4 times.
natali 33 [55]
Hi!!!! I think the answer is B or D! Have a nice day!!
5 0
3 years ago
Read 2 more answers
No clue what to do here. Can anyone help???
ICE Princess25 [194]

Answer:

try the app socratic Step-by-step explanation:

8 0
3 years ago
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