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Andre45 [30]
Answer:
the one real zero is in the interval (-1, 0)
Step-by-step explanation:
Descartes' rule of signs tells you there are 0 or 2 positive real zeros. Changing the signs of the odd-degree terms and applying that rule again tells you there is one negative real zero. At the same time, those coefficients (-3, -5, -5, +7) have a negative sum, so you know ...
f(-1) = -6
f(0) = +7
so there is a zero in the interval (-1, 0).
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You can try a few values between x=0 and x=10 to see what the function does in that part of the graph. You find ...
f(1) = 10
f(2) = 21
f(3) = 58
So, it is safe to conclude that there are no real zeros for x > 0.
The only real zero of f(x) is in the interval (-1, 0).
_____
I like to use a graphing calculator for problems like this.
Answer:
Step-by-step explanation:
-1/5
-1/7
-1/8
-1/9
-1/10
0
1/6
1/5
1/4
1/3
Answer:
(a)

(b)

(c)

Step-by-step explanation:
(a)
Simply evaluate (a+h) in the function:

(b)
Evaluate (a) in the function:

Using the previous answers lets calculate f(a+h)-f(a)

(c) To find the rate of change of f(a+1) when a=7 we need to calculate its derivate at that point:

Hi!!!! I think the answer is B or D! Have a nice day!!
Answer:
try the app socratic Step-by-step explanation: