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IRINA_888 [86]
3 years ago
6

the sum of three numbers is 45. the second of the three numbers is three more than twice the first number, x. the third number i

s two more than the first number, x. which equation can be used to solve for the first number, x?
Mathematics
2 answers:
TiliK225 [7]3 years ago
6 0
Your equation is x + (3+2x) + (2+x) = 45
x being the first number, (3+2x) being the second, and (2+x) being the third.
not sure if i was supposed to try to simplify. hope this helps!!
malfutka [58]3 years ago
4 0

Answer:

x + (2x + 3) + (x + 2) = 45

Step-by-step explanation:

Here, x represents the first number,

Since, second number is three more than twice the first number,

⇒ Second number = 2x + 3,

The third number is two more than the first number,

⇒ Third number = x + 2

Thus, the sum of these numbers = x + (2x + 3) + (x + 2)

According to the question,

Total sum = 45

⇒ x + (2x + 3) + (x + 2) = 45

Which is the required equation.

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