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prisoha [69]
3 years ago
8

What are the requirements for chemical labels?

Mathematics
2 answers:
Masja [62]3 years ago
8 0

Includes critical information you need to identify the chemical , Includes warnings about the chemical , Legible are the requirements for chemical labels

<u>Step-by-step explanation:</u>

Labels need to produce guidance on how to manage the chemical so that chemical users are notified about how to guard themselves.  That data about chemical hazards be dispatched on labels using quick visual notations (Legible)  to inform the user, granting instant identification of the hazards.

Labels, as described in the HCS, are a relevant group of written, printed or graphic information elements concerning a hazardous chemical that are attached to, printed on, or added to the immediate container of a hazardous chemical, or to the outside packaging.

Romashka [77]3 years ago
5 0

Answer:

Its all the choices, theres another choice too.  So all four choices are correct, not just these three.

Step-by-step explanation:

I took the test

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olga nikolaevna [1]

Answer: (3, -1)

Step-by-step explanation:

y = |x-3|-1

When y=|x|, vertex is (0, 0).

Now, let's translate the graph so it becomes y = |x-3|-1.

|x| ==> |x-3|         Translate the graph 3 units to the right

Vertex: (0+3, 0) ==> (3, 0)

|x-3| ==> |x-3|-1     Translate the graph 1 unit down

Vertex: (3, 0-1) ==> (3, -1)

Vertex: (3, -1)

7 0
2 years ago
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Vadim26 [7]

Answer:

3/6

Step-by-step explanation:

I think it is asking for an answer choice equal to 1/2, and 3/6 is equal to 1/2.

Do you have a picture of the actual question?

6 0
2 years ago
Find the are of the SHADED region.
Mazyrski [523]
First find the area of the parallelogram


Area of parallelogram = b x h
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Then find area of kite

Area of kite = (xy)/2
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= 42

Now we are gonna subtract the area of the kite from the area of the parallelogram.

84 - 42 = 42

Therefore the area of the shaded region is 42.
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PLEASE HELP! WILL MARK BRAINLIEST!
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answer:

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6 0
4 years ago
Read 2 more answers
Are composite numbers closed under multiplication
MrMuchimi

Answer:

Remember that for a subset of a ring to be an ideal it must be closed under addition and under taking multiples by elements of the ring, and in this case the set of all composite integers is not closed under addition.

Step-by-step explanation:

3 0
3 years ago
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