Let's call a child's ticket 
and an adult's ticket 
. From this, we can say:
,
since 116 tickets are sold in total.
Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus
.
Given these values, we can say:
,
since each adult ticket costs 17,000 and each child's ticket costs 12,750, and these costs sum to 1,653,250.
Now, we have two equations:
Let's solve:
- Find on its own, which will allow us to substitute it into the first equation
- Substitute in
for
- Apply the Distributive Property
- Subtract 1972000 from both sides of the equation and multiply both sides by -1
We have now found that 75 child's tickets were sold. Thus,
,
41 adult tickets were sold as well.
In sum, 41 adult tickets were sold along with 75 child tickets.
9 :
Given,
Perimeter = 88 units
Base = x + 4
Height = x - 6
= > Perimeter of Rectangle = 2( base + height )
= > 88 = 2{ ( x + 4 ) + ( x - 6 ) }
= > 88 / 2 = { x + 4 + x - 6 }
= > 44 = 2x - 2
= > 46 = 2x
= > 46 / 2 = x
= > 23 = x
Therefore,
Length of base = ( x + 4 ) units = ( 23 + 4 ) units = 27 units
Length of height = ( x - 6 ) units = ( 23 - 6 ) units = 17 units
10 :
Given,
First integer = x
Second integer = x + 2
Third Integer = x + 4
Given that the sum of all integers is 36
= > ( x ) + ( x + 2 ) + ( x + 4 ) = 36
= > x + x + 2 + x + 4 = 36
= > 3x + 6 = 36
= > 3x = 30
= > ( 3x ) ÷ ( 3 ) = ( 30 ) ÷ ( 3 )
= > x = 10
Value of first integer = x = 10
Answer:
option b
6 C 2 + 6
Step-by-step explanation:
Given in the question that,
number of pink beans = 87
number of purple beans = 74
number of white beans = 35
number of black beans = 70
number of orange beans = 25
number of green beans = 47
<h3>Step 1</h3>
if two beans selected are different
6 C 2
(6 colours of beans)
<h3>Step 2</h3>
if two beans selected are same
6 C 1 = 6
(6 colours of beans)
<h3>Step 3 </h3>
total sample space will be
6 C 2 + 6
The two triangles are isosceles.
Both triangles have the equals sides equal to 6
Both ∠ 1 and the ∠2 are the opposite angles to the different side of their respective triangles.
The opposite side to ∠ 1 is shorter than the opposite side to ∠ 2, which implies that ∠1 is less than ∠2.
Then the inequality that relates those angles is
∠1 < ∠2
What? This isn’t a question
