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Lapatulllka [165]
3 years ago
9

Mike is riding his bike 8 mi./hr northwest, and Shelly is riding her bike 11 mi./hr southwest. Both are headed for the intersect

ion of the two bike paths. At what rate are the bikes approaching each other when Mike is 0.2 mi. and Shelly is 0.5 mi. from the intersection?
Mathematics
1 answer:
Assoli18 [71]3 years ago
4 0

Answer: GLOBAL WARMING FOESNT EXIST

Step-by-step explanation: STOP RIDING BIKES MORE CARS

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C=-4 D=5 P=2 Q=-1<br><br> 4cd×10×2p÷50d+20q=??
nata0808 [166]
This is very simple; don't you worry.
     Let's start by breaking down the problem so that it's not overwhelming.
For now, we're only going to focus on the very beginning of the problem -- 4c.
     When a number is next to a letter with no signs in between (in terms of this kind of math), the number is called a coefficient and the letter is called a variable. When you see this in math, it means that the coefficient is being multiplied by the variable. But how do you know what the variable is?
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     What we just did there, changing 4c to 4 multiplied by 4, is called substitution. You just substituted the c with 4. Now you know that to solve this, you need to use the method of substitution. What do you get if you substitute all of the variables with the numbers they equal (as shown above)...?

((4*-4)*5)((10(2*2))/(50(5)))+20(-1). You didn't use parentheses to separate the term /50d + 20q, so I'm assuming that the first part of the problem is only divided by just 50d, and not 50d+20q. In the future, be sure to clarify with parentheses. Anyway...
     ((4*-4)*5)((10(2*2))/(50(5)))+20(-1).<span> Do NOT let this scare you. All the parentheses do is help you see what is being multiplied. All that's left is simple order of operations! You should get -<em>340 </em>as your answer.</span>
7 0
3 years ago
A pizza pan is removed at 9:00 PM from an oven whose temperature is fixed at 450°F into a room that is a constant 70°F. After 5​
gladu [14]

Answer:

A) It will get to a temperature of 125°F at 9:19 PM

B) It will get to a temperature of 150°F at 9:16 PM

C) as time passes temperature approaches the initial temperature of 450°F

Step-by-step explanation:

We are given;

Initial temperature; T_i = 450°F

Room temperature; T_r = 70°F

From Newton's law of cooling, temperature after time (t) is given as;

T(t) = T_r + (T_i - T_r)e^(-kt)

Where k is cooling rate and t is time after the initial temperature.

Now, we are told that After 5​ minutes, the temperature is 300°F.

Thus;

300 = 70 + (450 - 70)e^(-5k)

300 - 70 = 380e^(-5k)

230/380 = e^(-5k)

e^(-5k) = 0.6053

-5k = In 0.6053

-5k = -0.502

k = 0.502/5

k = 0.1004 /min

A) Thus, at temperature of 125°F, we can find the time from;

125 = 70 + (450 - 70)e^(-0.1004t)

125 - 70 = 380e^(-0.1004t)

55/380 = e^(-0.1004t)

In (55/380) = -0.1004t

-0.1004t = -1.9328

t = 1.9328/0.1018

t ≈ 19 minutes

Thus, it will get to a temperature of 125°F at 9:19 PM

B) Thus, at temperature of 150°F, we can find the time from;

150 = 70 + (450 - 70)e^(-0.1004t)

150 - 70 = 380e^(-0.1004t)

80/380 = e^(-0.1004t)

In (80/380) = -0.1004t

-0.1004t = -1.5581

t = 1.5581/0.1004

t ≈ 16 minutes.

Thus, it will get to a temperature of 150°F at 9:16 PM

C) As time passes which means as it approaches to infinity, it means that e^(-kt) gets to 1.

Thus,we have;

T(t) = T_r + (T_i - T_r)

T_r will cancel out to give;

T(t) = T_i

Thus, as time passes temperature approaches the initial temperature of 450°F

6 0
3 years ago
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