All categories

3 years ago

The formula for the volume of a sphere is V= 4/3 pi r cubed. what is the formula solved for r

2 answers:

6 0

V=4/3π r^3

(3/4)V=π r^3

3V/4π = r^3

third root√(3V/4π)

Hope this helps!
and May the Force Be With You

-Jabba

Luda [366]3 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

Simplify: –4(x – 5) + 3(a – 7)

Serga [27]

-4 (x - 5) + 3 (a - 7)

First, expand your problem. / Your problem should look like: -4x + 20 + 3a - 21
Second, simplify. / Your problem should look like: -4x + 3a - 1

Answer: -4x + 3a - 1 (C)

8 0

3 years ago

Read 2 more answers

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0

3 years ago

Jacob is a plumber. Due to increased material costs, he puts all his prices up by 7%. He now chargers R320 per hour for her serv

Lorico [155]

Answer:

R290.1

Step-by-step explanation:

Let

x = charge before he put his prices up

New charge = R320

Percentage increase in price = 7%

x + 7% of x = 320

x + 0.07 * x = 320

x + 0.07x = 320

1.07x = 320

x = 320/1.07

x = 299.06542056074

Approximately

x = R290.1

Charge before he put his prices up = R290.1

4 0

2 years ago

Please need help Find area of shaded region. Round to the nearest tenth

vlabodo [156]

Answer:

818.4 in²

Step-by-step explanation:

The area (A) of the shaded region is

A = area of circle - ( area of white sector + area of triangle )

= ( π × 27.8²) - (π × 27.8² × $\frac{210}{360}$ +(0.5 × 27.8 ×27.8 × sin150°)

= 2427.95 - (1416.30 + 193.21 )

= 2427.95 - 1609.51 ≈ 818.4 in²

7 0

3 years ago

Please help me answer this question

Alekssandra [29.7K]

10 divided by 200= 20

4 0

3 years ago

Read 2 more answers