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grandymaker [24]
2 years ago
7

Which graph represents the solution set of the inequality x+2> 6?

Mathematics
1 answer:
lisabon 2012 [21]2 years ago
4 0

Answer:

Hi, there the answer C because in the inequality there is a line underneath it means the dot has to be closed

Step-by-step explanation:

You might be interested in
What are the x-intercepts ?
NeTakaya

Answer:

(3,0),(2,0)

Step-by-step explanation:

6 0
3 years ago
A slitter assembly contains 48 blades. Five blades are selected at random and evaluated each day of sharpness. If any dull blade
Alex73 [517]

Answer:

Part a

The probability that assembly is replaced the first day is 0.7069.

Part b

The probability that assembly is replaced no replaced until the third day of evaluation is 0.0607.

Part c

The probability that the assembly is not replaced until the third day of evaluation is 0.2811.

Step-by-step explanation:

Hypergeometric Distribution: A random variable x that represents number of success of the n trails without replacement and M represents number of success of the N trails without replacement is termed as the hypergeometric distribution. Moreover, it consists of fixed number of trails and also the two possible outcomes for each trail.

It occurs when there is finite population and samples are taken without replacement.

The probability distribution of the hyper geometric is,

P(x,N,n,M)=\frac{(\limits^M_x)(\imits^{N-M}_{n-x})}{(\limits^N_n)}

Here x is the success in the sample of n trails, N represents the total population, n represents the random sample from the total population and M represents the success in the population.

Probability that at least one of the trail is succeed is,

P(x\geq1)=1-P(x

(a)

Compute the probability that the assembly is replaced the first day.

From the given information,

Let x be number of blades dull in the assembly are replaced.

Total number of blades in the assembly N = 48.

Number of blades selected at random from the assembly  n= 5

Number of blades in an assembly dull is M  = 10.

The probability mass function is,

P(X=x)=\frac{[\limits^M_x][\limits^{N-M}_{n-x}]}{[\limits^N_n]};x=0,1,2,...,n\\\\=\frac{[\limits^{10}_x][\limits^{48-10}_{5-x}]}{[\limits^{48}_5]}

The probability that assembly is replaced the first day means the probability that at least one blade is dull is,

P(x\geq 1)=1- P(x

(b)

From the given information,

Let x be number of blades dull in the assembly are replaced.

Total number of blades in the assembly  N = 48

Number of blades selected at random from the assembly  N = 5

Number of blades in an assembly dull is  M = 10

From the information,

The probability that assembly is replaced (P)  is 0.7069.

The probability that assembly is not replaced is (Q)  is,

q=1-p\\= 1-0.7069= 0.2931

The geometric probability mass function is,

P(X = x)= q^{x-1} p; x =1,2,....=(0.2931)^{x-1}(0.7069)

The probability that assembly is replaced no replaced until the third day of evaluation is,

P(X = 3)=(0.2931)^{3-1}(0.7069)\\=(0.2931)^2(0.7069)= 0.0607

(c)

From the given information,

Let x be number of blades dull in the assembly are replaced.

Total number of blades in the assembly   N = 48

Number of blades selected at random from the assembly  n = 5

Suppose that on the first day of the evaluation two of the blades are dull then the probability that the assembly is not replaced is,

Here, number of blades in an assembly dull is M  = 2.

P(x=0)=\frac{(\limits^2_0)(\limits^{48-2}_{5-0})}{\limits^{48}_5}\\\\=\frac{(\limits^{46}_5)}{(\limits^{48}_5)}\\\\= 0.8005

Suppose that on the second day of the evaluation six of the blades are dull then the probability that the assembly is not replaced is,

Here, number of blades in an assembly dull is M  = 6.

P(x=0)=\frac{(\limits^6_0)(\limits^{48-6}_{5-0})}{(\limits^{48}_5)}\\\\=\frac{(\limits^{42}_5}{(\limits^{48}_5)}\\\\= 0.4968

Suppose that on the third day of the evaluation ten of the blades are dull then the probability that the assembly is not replaced is,

Here, number of blades in an assembly dull is M

= 10.

P(x\geq 1)=1- P(x

 

The probability that the assembly is not replaced until the third day of evaluation is,

P(The assembly is not replaced until the third day)=P(The assembly is not replaced first day) x P(The assembly is not replaced second day) x P(The assembly is replaced third day)

=(0.8005)(0.4968)(0.7069)= 0.2811

5 0
3 years ago
Y - 3 = -2(x -1)<br> How do i do this?
Masja [62]

Answer: -2

Step-by-step explanation:

y-intercept: (0,5)

5 0
3 years ago
What are the solutions to the equation <br><img src="https://tex.z-dn.net/?f=2%20%7Cx%20-%202%7C%20%20-%208%20%3D%2020" id="TexF
leva [86]

The solutions of the equation are -12 and 16

Step-by-step explanation:

Absolute value describes the distance of a number on the number line from 0 without considering which direction from zero the number lies. The absolute value of a number is never negative, if IxI = a, where a > 0, then

  • x = a
  • x = -a

∵ 2Ix - 2I - 8 = 20

- At first add 8 to both sides

∴ 2Ix - 2I = 28

- Then divide both sides by 2

∴ Ix - 2I = 14

Now By using the notes above equate x - 2 by 14 and -14

∵ x - 2 = 14

- Add 2 to both sides

∴ x = 16

∵ x - 2 = -14

- Add 2 to both sides

∴ x = -12

The solutions of the equation are -12 and 16

Learn more:

You can learn more about solving equations in brainly.com/question/2386054

#LearnwithBrainly

4 0
3 years ago
Which of the following is equal to 5/8÷2/7?
natta225 [31]

Answer:

5/8 * 7/2

Step-by-step explanation:

Whenever you divide fractions, you can use the 'keep change flip' method.

You keep 5/8, change the division sign to multiplication, and then flip the second fraction.

1. 5/8 / 7/2  -  Keep 5/8

2. 5/8 * 7/2  -  Change division sign

3. 5/8 * 2/7  -  Flip the second fraction, 7/2 -> 2/7

5 0
3 years ago
Read 2 more answers
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