<u>Answer:</u> The pH of the solution is 4.14
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
Molarity of NaOH = 1 M
Volume of solution = 20 mL
Putting values in above equation, we get:
Molarity of acetic acid solution = 0.26 M
Volume of solution = 100 mL
Putting values in above equation, we get:
The chemical reaction for NaOH and acetic acid follows the equation:
<u>Initial:</u> 0.100 0.020
<u>Final:</u> 0.080 - 0.020
Volume of solution = 20 + 100 = 120 mL = 0.120 L (Conversion factor: 1 L = 1000 mL)
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
We are given:
= negative logarithm of acid dissociation constant of acetic acid = 4.74
pH = ?
Putting values in above equation, we get:
Hence, the pH of the solution is 4.14