Answer:
The specific heat of zinc is 0.361 J/g°C
Explanation:
<u>Step 1:</u> Data given
44.0 J needed
Mass of solid zinc = 10.6 grams
Initial temperature = 24.9 °C
Final temperature = 36.4 °C
<u>Step 2</u>: Calculate the specific heat of zinc
Q = m*c*ΔT
⇒ with Q = heat (in Joule) = 44.0 J
⇒ with m = the mass of the solid zinc = 10.6 grams
⇒ with c = the specific heat of the zinc = TO BE DETERMINED
⇒ with ΔT = The change in temperature = T2-T1 = 36.4 °C - 24.9 °C = 11.5 °C
44.0 J = 10.6 grams * c * 11.5°C
c = 44.0 J / (10.6g * 11.5 °C)
c = 0.361 J/g°C
The specific heat of zinc is 0.361 J/g°C
Moles pf mgcl2= 2,11/M mgcl2=2,11/95= 0,0222
Molarity=0,0222/1,5=0,0148 M.
I hope this is correct.
Answer:
Distance cover by school bus = 149.5 miles
Explanation:
Given:
Velocity of school bus = 65 mph
Time taken by school bus = 2.3 hours
Find:
Distance cover by school bus
Computation:
Distance cover = Velocity x Time taken
Distance cover by school bus = Velocity of school bus x Time taken by school bus
Distance cover by school bus = 65 x 2.3
Distance cover by school bus = 149.5 miles