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ahrayia [7]
3 years ago
9

Solve 3x^2 = −12x − 15.

Mathematics
2 answers:
Artyom0805 [142]3 years ago
6 0
-2+i, -2-i are your two answers, you have to move everything to one side and solve
vitfil [10]3 years ago
4 0
3x^2+12x+15=0


Then divide by 3 to get the x by itself. 
x^2+4x+5=0


Factor to (x+5) (x-1) and solve for the two values of x.
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the artist goes to the store to buy brushes and small cans of paint. he pays $94. he buys 8 brushes that cost $5 each. the rest
sertanlavr [38]
Pays $94
brushes = $40
94 - 40 = 54
54 ÷ 6 = 9
each can of paint costs $9
7 0
3 years ago
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Maya runs a farm stand that sells raspberries and blueberries. Each pound of raspberries sells for $1 and each pound of blueberr
aniked [119]

30 pounds of raspberries and 50 pounds of blueberries are sold

<em><u>Solution:</u></em>

Let "a" be the pounds of raspberries sold

Let "b" be the pounds of blueberries sold

Cost per pound of raspberry = $ 1

Cost per pound of blue berry = $ 3.25

<em><u>Maya made $192.50 from selling a total of 80 pounds of raspberries and blueberries</u></em>

Therefore,

a + b = 80

a = 80 - b ------- eqn 1

<em><u>Maya made $192.50. Therefore, frame a equation as:</u></em>

pounds of raspberries sold x Cost per pound of raspberry + pounds of blueberries sold x Cost per pound of blue berry = 192.50

a \times 1 + b \times 3.25 = 192.50

a + 3.25b = 192.50 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

80 - b + 3.25b = 192.50

2.25b = 192.50 - 80

2.25b = 112.5

Divide both sides by 2.25

b = 50

<em><u>Substitute b = 50 in eqn 1</u></em>

a = 80 - 50

a = 30

Thus 30 pounds of raspberries and 50 pounds of blueberries are sold

3 0
3 years ago
Alex borrowed $12.50 from his friend Danilo. He paid him back $8.75. How much does he still owe?
Arisa [49]
$3.75 Because $12.50 - $8.75=$3.75

7 0
3 years ago
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suppose that y varies jointly with x and z. Find your when x=3 and z=5 , given that y=72 when x=6 and z=4
Hitman42 [59]
Y α xz

y = kxz             y = 72, when x = 6, and z = 4

72 = k*6*4

72 = k*24

24k = 72

k = 72/24

k = 3.

<span>y = kxz    
</span>
<span>y = 3xz    </span>

Finding y, when x = 3, z = 5.

y = 3xz

y = 3*3*5

y = 45
3 0
3 years ago
5. Can someone explain how to solve this?
zhannawk [14.2K]

Answer:

AC = 5 cm

BD = 12.5 cm (3 sf) [or 2 × root 39]

BE = 6.93 cm (3 sf) [or 4 × root 3]

Step-by-step explanation:

CE = 8cm [CE is radius of circle]

AC + 3 = 8

<u>A</u><u>C</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>c</u><u>m</u>

BC = 8cm [BC is a radius of circle]

(AC)^2 + (AB)^2 = (BC)^2 [Pythagoras theorem]

25 + (AB)^2 = 64

AB = 6.2450 cm (5 sf) [or root 39]

BD = 2(BA)

= 2(6.2450)

<u>B</u><u>D</u><u> </u><u>=</u><u> </u><u>1</u><u>2</u><u>.</u><u>5</u><u> </u><u>c</u><u>m</u><u> </u><u>(</u><u>3</u><u> </u><u>s</u><u>f</u><u>)</u><u> </u><u>[</u><u>o</u><u>r</u><u> </u><u>2</u><u> </u><u>×</u><u> </u><u>r</u><u>o</u><u>o</u><u>t</u><u> </u><u>3</u><u>9</u><u>]</u>

(BA)^2 + (AE)^2 = (BE)^2 [Pythagoras theorem]

39 + 9 = (BE)^2

<u>B</u><u>E</u><u> </u><u>=</u><u> </u><u>6</u><u>.</u><u>9</u><u>3</u><u> </u><u>c</u><u>m</u><u> </u><u>(</u><u>3</u><u> </u><u>s</u><u>f</u><u>)</u><u> </u><u>[</u><u>o</u><u>r</u><u> </u><u>4</u><u> </u><u>×</u><u> </u><u>r</u><u>o</u><u>o</u><u>t</u><u> </u><u>3</u><u>]</u>

6 0
3 years ago
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