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2 years ago

What value is a discontinuity of x squared plus 5 x plus 2, all over x squared plus 2 x minus 35?

Mathematics

2 answers:

juin [17]2 years ago

7 0

Answer:

f(x) = (x^2 + 5x + 2)/(x^2 + 2x - 35)

Step-by-step explanation:

azamat2 years ago

4 0

F(x) = (x^2 + 5x + 2)/(x^2 + 2x - 35) 

there are NO DISCONTINUITIES for this function... 

there are two vertical asymptotes: 

x = - 7 and x = 5 

there is a horizontal asymptote at: y = 1

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The terminal side of an angle in standard position passes through P(15, –8). What is the value of sine theta? sine theta = fifte

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The value of sine theta = negative eight-seventeenths ⇒ 2nd

Step-by-step explanation:

Let us revise the quadrant of an angle its terminal side passes through a given point

If the given point is (x , y), then the angle lies in the 1st quadrant
If the given point is (-x , y), then the angle lies in the 2nd quadrant
If the given point is (-x , -y), then the angle lies in the 3rd quadrant
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∵ The terminal side of angle Ф passes through P (15 , -8)

∵ x = 15 and y = -8

- P is (x , -y), then the angle Ф lies in the 4th quadrant

∵ The terminal side of angle Ф is the hypotenuse of a right

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- Use Pythagoras Theorem to find the length of the hypotenuse

∴ Hypotenuse = $\sqrt{(15)^{2}+(-8)^{2}}=17$ units

∵ sinФ = $\frac{opposite}{hypotenuse}$

∵ The side opposite to Ф is -8

∵ The hypotenuse is 17

∴ sinФ = $\frac{-8}{17}$

The value of sine theta = negative eight-seventeenths

Learn more:

You can learn more about the trigonometry function in brainly.com/question/4924817

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