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WINSTONCH [101]

2 years ago

9

Which transformations could have occurred to map △ABC to △A"B"C"?a rotation and a dilationa rotation and a reflectiona reflectio

n and a dilationa translation and a dilation edg 2022

1 answer:

Tomtit [17]2 years ago

6 0

Answer:

D, dialation and rotation on edge

Step-by-step explanation:

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What is the 50th term of the sequence that begins with -6, 0, 6, 12...

vazorg [7]

Answer:

The 50th term is 288.

Step-by-step explanation:

A sequence that each term is related with the prior by a sum of a constant ratio is called a arithmetic progression, the sequence in this problem is one of those. In order to calculate the nth term of a setence like that we need to use the following formula:

an = a1 + (n-1)*r

Where an is the nth term, a1 is the first term, n is the position of the term in the sequence and r is the ratio between the numbers. In this case:

a50 = -6 + (50 - 1)*6

a50 = -6 + 49*6

a50 = -6 + 294

a50 = 288

The 50th term is 288.

5 0

3 years ago

Jollibee employs a total of 10 cashiers and 15 kitchen crews. The manager selects a team of 2 cashiers and

Airida [17]

Answer:

The manager can select a team in 61425 ways.

Step-by-step explanation:

The order in which the cashiers and the kitchen crews are selected is not important. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In how many ways can the manager select a team?

2 cashiers from a set of 10.

4 kitchen crews from a set of 15. So

$T = C_{10,2}*C_{15,4} = \frac{10!}{2!(10-2)!}*\frac{15!}{4!(15-4)!} = 45*1365 = 61425$

The manager can select a team in 61425 ways.

7 0

2 years ago

A members-only speaker series allows people to join for $28 and then pay $4 for every event attended. What is the total cost for

wariber [46]

Given:

Joining fee = $28

Fee of each event = $4

To find:

Total cost for someone to attend 4 events.

Solution:

Let the number of events be x and total fee be y.

Fee for 1 event = $4

Fee for x events = $4x

Joining fee remains constant. So, the total fee is

$y=28+4x$

Substitute x=4 in this equation.

$y=28+4(4)$

$y=28+16$

$y=44$

Therefore, total cost of 4 events is $44.

8 0

3 years ago

What is the least common denominator of 4/5 and 1/10

antiseptic1488 [7]

The least common denominator for the question you have supplied me with is 10. The least common multiple of the denominators, 5 and 10, is 10, making the LCD 10.

4 0

3 years ago

Read 2 more answers

1. Write your answer using only<br> positive exponents.<br><br> (3ab^3c^-1)^3

marishachu [46]

Answer:

$(\frac{{3ab^{3}}}{c^{1}} )^{3}$

Step-by-step explanation:

$(3ab^{3} c^{-1} )^{3} =(\frac{{3ab^{3}}}{c^{1}} )^{3}$

6 0

3 years ago

Read 2 more answers