Answer:
The 50th term is 288.
Step-by-step explanation:
A sequence that each term is related with the prior by a sum of a constant ratio is called a arithmetic progression, the sequence in this problem is one of those. In order to calculate the nth term of a setence like that we need to use the following formula:
an = a1 + (n-1)*r
Where an is the nth term, a1 is the first term, n is the position of the term in the sequence and r is the ratio between the numbers. In this case:
a50 = -6 + (50 - 1)*6
a50 = -6 + 49*6
a50 = -6 + 294
a50 = 288
The 50th term is 288.
Answer:
The manager can select a team in 61425 ways.
Step-by-step explanation:
The order in which the cashiers and the kitchen crews are selected is not important. So we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.

In how many ways can the manager select a team?
2 cashiers from a set of 10.
4 kitchen crews from a set of 15. So

The manager can select a team in 61425 ways.
Given:
Joining fee = $28
Fee of each event = $4
To find:
Total cost for someone to attend 4 events.
Solution:
Let the number of events be x and total fee be y.
Fee for 1 event = $4
Fee for x events = $4x
Joining fee remains constant. So, the total fee is

Substitute x=4 in this equation.



Therefore, total cost of 4 events is $44.
The least common denominator for the question you have supplied me with is 10. The least common multiple of the denominators, 5 and 10, is 10, making the LCD 10.