F(x)= ∫ln²x/x dx= ∫ln²xd(lnx) cause d(lnx)= (lnx)'dx=1/x dx
= ln³x/3 +C with C is constant
In addition, we have f(2)=6, so we have 6=ln³2/3+C
or C= 6- <span>ln³2/3
And f(x)= </span>ln³x/3+ <span> 6- </span><span>ln³2/3</span>
Answer:
<em>x = 3 and y = 0</em>
Step-by-step explanation:
3y+x=3
-2y+5x=15
Isolate y in 3y + x = 3 :

Substitute
in -2y + 5x = 15 :

Simplify the equation :

Isolate x in
:
Proving x = 3
Isolate y in
:
Proving y = 0
Your solved system of equations are x being 3, and y being 0.
The distance between those two points is 8 because its a straight line...
Answer:
The answer is 40 can I please get brainleist