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Basile [38]
2 years ago
6

The example of a beach ball with a ping pong ball inside of it can be used to imagine the relationship between what two entities

?
Mathematics
1 answer:
Nookie1986 [14]2 years ago
3 0

The celestial sphere and Earth is the example of a beach ball with a ping pong ball inside of it can be used to imagine the relationship between what two entities.

The heavenly sphere is what Why is this old idea still relevant today?

  • Ancient people used the celestial sphere to describe the visible universe.
  • Although our understanding of the cosmos has changed, the concept of a celestial sphere is still prevalent because it provides a straightforward perspective on the stars that is useful for navigation.

Which phrase most accurately sums up the celestial sphere?

The entire sky as seen from Earth is portrayed by the celestial sphere. Keep in mind that the celestial sphere is intended to depict the sky as it appears from our planet rather than physical reality.

Learn more about celestial sphere

brainly.com/question/13196153

#SPJ4

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In the diagram below, KL = 12 and LM = 8. Which additional facts would guarantee that JKLM is a parallelogram? Check all that ap
salantis [7]
I don't know the last point, but I'm going to assume it's N.
MN = 12 and KN = 8.
That would make this a rectangle.
All angles add up to 360.

4 0
3 years ago
Read 2 more answers
Which of the following is the midsegment for A ACE?
11111nata11111 [884]

Answer:

A. DB

Step-by-step explanation:

The line BD is the mid segment because it connects the midpoints of line segment AC and CE

5 0
3 years ago
Graph the line y = kx +1 if it is known that the point M belongs to it: M(1,3)
tigry1 [53]

Answer:

M(x,y) = (1,3) belongs to the line y = 2\cdot x +1. Please see attachment below to know the graph of the line.

Step-by-step explanation:

From Analytical Geometry we know that a line is represented by this formula:

y=k\cdot x + b

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

k - Slope, dimensionless.

b - y-Intercept, dimensionless.

If we know that b = 1, x = 1 and y = 3, then we clear slope and solve the resulting expression:

k = \frac{y-b}{x}

k = \frac{3-1}{1}

k = 2

Then, we conclude that point M(x,y) = (1,3) belongs to the line y = 2\cdot x +1, whose graph is presented below.

3 0
3 years ago
Find the length of the following​ two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16
andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)}     dt

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)}     dt

Doing the operations inside of the brackets the derivatives are:

1 ) (\frac{d((1/2)t^2)}{dt} )^2= t^2

2) \frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1

Entering these values of the integral is

r(t)= \int\limits^{16}_{0}  \sqrt{t^2 +2t+1}     dt

It is possible to factorize the quadratic function and the integral can reduced as,

r(t)= \int\limits^{16}_{0} (t+1)  dt= \frac{t^2}{2} + t

Thus, evaluate from 0 to 16

\frac{16^2}{2} + 16

The value is r= 144 units

5 0
3 years ago
This doesn't tell me anything what is this supposed to mean, can you please explain it!!
KiRa [710]
Normally I'd love to help, but put in a picture. I'm confused.
7 0
3 years ago
Read 2 more answers
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