Let the square base of the container be of side s inches and the height of the container be h inches, then
Surface are of the container, A = s^2 + 4sh
For minimum surface area, dA / ds + dA / dh = 0
i.e. 2s + 4h + 4s = 0
6s + 4h = 0
s = -2/3 h
But, volume of container = 62.5 in cubed
i.e. s^2 x h = 62.5
(-2/3 h)^2 x h = 62.5
4/9 h^2 x h = 62.5
4/9 h^3 = 62.5
h^3 = 62.5 x 9/4 = 140.625
h = cube root of (140.625) = 5.2 inches
s = 2/3 h = 3.47
Therefore, the dimensions of the square base of the container is 3.47 inches and the height is 5.2 inches.
The minimum surface area = s^2 + 4sh = (3.47)^2 + 4(3.47)(5.2) = 12.02 + 72.11 = 84.13 square inches.
180-104=76
76x2=152
Answer is 152
Answer:
m∠C = 44°
Step-by-step explanation:
In ΔCDE,
m∠C=(4x−16) ∘
m∠D=(6x−1) ∘
m∠E=(4x−13) ∘ .
The sum of angles in a triangle = 180°
Step 1
We solve for x
m∠C + m∠D + m∠E
(4x−16)° + (6x−1)° + (4x−13)° = 180°
4x - 16 + 6x - 1 + 4x - 13 = 180°
4x + 6x + 4x -16 - 1 - 13 = 180°
14x - 30 = 180°
14x = 180+ 30
14x = 210
x = 210/14
x = 15
Step 2
Find m∠C
m∠C = (4x−16)°
m∠C = (4 × 15 - 16)°
m∠C = (60 - 16)°
m∠C = 44°
It's 10. I hope this helps!
Answer:
All real numbers
Step-by-step explanation:
First simplify it and it becomes:-
4x - 8
Now, the domain will be all real numbers as it satisfy them all.
Now, for range write the expression in terms of y i.e.
y = 4x - 8
>> x = (y + 8)/4
Now y also satisfies all real numbers.
Hence, the answer is above.
