3 years ago

Help ..................

Mathematics

1 answer:

Alexus [3.1K]3 years ago

7 0

Pythagorean Theorm Unit? I got you!

It would be C, about 63.07

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Which of the following functions are solutions of the differential equation y" – 4y' + 3y = 0? CA. y(x) = xe-3x B. y(x) = et C.

Kipish [7]

Answer:

$y(x)=c_1e^{x}+c_2e^{3x}$

$y(x)=e^x$

$y(x)=e^{3x}$

Option B is correct. $y=e^t$

Step-by-step explanation:

Given: y''-4y'+3y = 0

It is a linear differential equation.

First we make characteristic equation.

$m^2-4m+3=0$

Now factor the equation and we get

$(m-3)(m-1)$

$m=1,3$

Here, we have two distinct root.

$y(x)=c_1e^{m_1t}+c_2e^{m_2t}$

Solution of differential equation:

$y(x)=c_1e^{x}+c_2e^{3x}$

where, c₁ and c₂ are constants.

Hence, The solution of the given differential equation is $y(x)=c_1e^{x}+c_2e^{3x}$

$y(x)=e^x$

$y(x)=e^{3x}$

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4 years ago

What is the slope of the line through (-9.6) and (-3, 9)?

xenn [34]

Answer:

1/2

Step-by-step explanation:

(-9,6), (-3,9)

y2 - y1 = 9 - 6 = 3

x2 - x1 = -3 - -9 = 6

= 3/6 = 1/2

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Answer:

It should be D

Step-by-step explanation:

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The answer you are looking for is C. (12)

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