Question

Which equation could generate the curve in the graph below?

Answer 1

Answer:

It's D. on EtDtGtE

Step-by-step explanation:

Answer 2

Answer:

y = 2x^2 + 8x + 8

Step-by-step explanation:

The graph touches the x axis at only one point.

so there is only one real solution.

If there is only one real solution then determinant =0

Now we find out the equation that has determinant 0

Determinant is $b^2 - 4ac$

Let find b^2 - 4ac for each equation

(a) $y = 9x^2 + 6x + 4$

a= 9 , b = 6 and c=4

$b^2-4ac= 6^2 - 4(9)(4) = -108$

determinant not equal to 0

(b) $y = 6x^2 – 12x – 6$

a= 6 , b = -12 and c=-6

$b^2-4ac= (-12)^2 - 4(6)(-6) = 288$

determinant not equal to 0

(c) $y = 3x^2 + 7x + 5$

a= 3 , b = 7 and c=5

$b^2-4ac= (7)^2 - 4(3)(5) = -11$

determinant not equal to 0

(d) $y = 2x^2 + 8x + 8$

a= 2 , b = 8 and c=8

$b^2-4ac= (8)^2 - 4(2)(8) = 0$

determinant equal to 0. So there is only one real solution.