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ddd [48]
3 years ago
6

Evaluate this problem 8²+18-2(6+2)÷4

Mathematics
2 answers:
ale4655 [162]3 years ago
4 0

I hope this helps. Good Luck!

vladimir2022 [97]3 years ago
3 0

8^2 + 18 - 2(6 + 2) / 4

Let's solve this problem using the PEMDAS rule. The PEMDAS rule gives us a reminder of how to solve expressions, etc., and which operations we will be completing first.

  1. Parentheses
  2. Exponents
  3. Multiplication
  4. Division
  5. Addition
  6. Subtraction

Keep in mind that PEMDAS should be written as PE(MD)(AS) because multiplication & division and addition & subtraction are in no particular order. You solve them from left to right.

Now let's solve this problem. First step to solving expressions are to write them out so you can clearly see them.

8^2 + 18 - 2(6 + 2) / 4

PEMDAS tells us to solve inside the parentheses first, so that is what we will be doing. Solve inside the parentheses and then rewrite your expression.

8^2 + 18 - 2(8) / 4

Now PEMDAS tells us to solve for exponents next. In this expression, 8 is being carried to the power of two, so that will be your next step. Solve for 8 to the power of two and then rewrite your expression.

64 + 18 - 2(8) / 4

Now we have the operations of: addition, subtraction, multiplication, and division left. According to PEMDAS, multiplication & division come before addition & subtraction. We will solve multiplication and division from left to right.

Look at the expression to find out which comes first, multiplication or division. In this expression, multiplication comes first (2 * 8), so solve multiplication first. Then rewrite your expression.

64 + 18 - 16 / 4

Now we have to solve division because it comes before addition & subtraction. Solve the division of 16 divided by 4 and then rewrite your expression.

64 + 18 - 4

The operations we have left are addition and subtraction. Following the PEMDAS rule, we will solve addition and subtraction from left to right because they are in no particular order.

Use the addition operation first because it comes first when looking the expression from left to right. Add 64 and 18 and then rewrite your expression.

82 - 4

The very last step in completing the simplification and evaluation of this problem is to subtract 4 from 82. Let's now complete this step, then you will have your final answer.

After subtracting 4 from 82, you are left with the answer of 78. Your final answer is \boxed {78}.

I hope this helped you greatly; just remember that you must use PEMDAS when trying to evaluate expressions! Have a great day and good luck on your homework. :)

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X+y+z=12<br> 6x-2y+z=16<br> 3x+4y+2z=28<br> What does x, y, and z equal?
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Answer:

x = 20/13 , y = 16/13 , z = 120/13

Step-by-step explanation:

Solve the following system:

{x + y + z = 12 | (equation 1)

6 x - 2 y + z = 16 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Swap equation 1 with equation 2:

{6 x - 2 y + z = 16 | (equation 1)

x + y + z = 12 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/6 × (equation 1) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+(4 y)/3 + (5 z)/6 = 28/3 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Multiply equation 2 by 6:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/2 × (equation 1) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+5 y + (3 z)/2 = 20 | (equation 3)

Multiply equation 3 by 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+10 y + 3 z = 40 | (equation 3)

Swap equation 2 with equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+8 y + 5 z = 56 | (equation 3)

Subtract 4/5 × (equation 2) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+(13 z)/5 = 24 | (equation 3)

Multiply equation 3 by 5:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+13 z = 120 | (equation 3)

Divide equation 3 by 13:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract 3 × (equation 3) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y+0 z = 160/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 2 by 10:

{6 x - 2 y + z = 16 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Add 2 × (equation 2) to equation 1:

{6 x + 0 y+z = 240/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract equation 3 from equation 1:

{6 x+0 y+0 z = 120/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 1 by 6:

{x+0 y+0 z = 20/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Collect results:

Answer:  {x = 20/13 , y = 16/13 , z = 120/13

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