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ddd [48]
3 years ago
6

Evaluate this problem 8²+18-2(6+2)÷4

Mathematics
2 answers:
ale4655 [162]3 years ago
4 0

I hope this helps. Good Luck!

vladimir2022 [97]3 years ago
3 0

8^2 + 18 - 2(6 + 2) / 4

Let's solve this problem using the PEMDAS rule. The PEMDAS rule gives us a reminder of how to solve expressions, etc., and which operations we will be completing first.

  1. Parentheses
  2. Exponents
  3. Multiplication
  4. Division
  5. Addition
  6. Subtraction

Keep in mind that PEMDAS should be written as PE(MD)(AS) because multiplication & division and addition & subtraction are in no particular order. You solve them from left to right.

Now let's solve this problem. First step to solving expressions are to write them out so you can clearly see them.

8^2 + 18 - 2(6 + 2) / 4

PEMDAS tells us to solve inside the parentheses first, so that is what we will be doing. Solve inside the parentheses and then rewrite your expression.

8^2 + 18 - 2(8) / 4

Now PEMDAS tells us to solve for exponents next. In this expression, 8 is being carried to the power of two, so that will be your next step. Solve for 8 to the power of two and then rewrite your expression.

64 + 18 - 2(8) / 4

Now we have the operations of: addition, subtraction, multiplication, and division left. According to PEMDAS, multiplication & division come before addition & subtraction. We will solve multiplication and division from left to right.

Look at the expression to find out which comes first, multiplication or division. In this expression, multiplication comes first (2 * 8), so solve multiplication first. Then rewrite your expression.

64 + 18 - 16 / 4

Now we have to solve division because it comes before addition & subtraction. Solve the division of 16 divided by 4 and then rewrite your expression.

64 + 18 - 4

The operations we have left are addition and subtraction. Following the PEMDAS rule, we will solve addition and subtraction from left to right because they are in no particular order.

Use the addition operation first because it comes first when looking the expression from left to right. Add 64 and 18 and then rewrite your expression.

82 - 4

The very last step in completing the simplification and evaluation of this problem is to subtract 4 from 82. Let's now complete this step, then you will have your final answer.

After subtracting 4 from 82, you are left with the answer of 78. Your final answer is \boxed {78}.

I hope this helped you greatly; just remember that you must use PEMDAS when trying to evaluate expressions! Have a great day and good luck on your homework. :)

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Answer: Distance between O and the line 1 is 3 inches.

Explanation:

Since we have given that

Distance between point A and the line 1 = 10 inches

Distance between point B and the line 1 = 4 inches

Total length of segment AB is given by

10+4=14\ inches

Since O is midpoint of the line segment AB.

so, AO is given by

\frac{14}{2}=7\ in.

Now, Distance between O and the line 1 is given by

10-7=3\ in.

Hence, Distance between O and the line 1 is 3 inches.

7 0
3 years ago
A​ 12-sided die is rolled. The set of equally likely outcomes is {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12} . Find the probability
Free_Kalibri [48]

Answer:

11/12

Step-by-step explanation:

Greater than 1: 2,3.... 12

P(greater than 1) = 11/12

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Hao bought a 16-pound bag of dog food. If his dog eats pound of food every day, for how many days will the bag of dog food last?
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Step-by-step explanation:

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If the original quantity is 15 and the new quantity is 19, estimate the percent change.
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(difference between original and new)/original * 100
(19-15)/15 * 100 =
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5 0
3 years ago
The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f
Sloan [31]

Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen  who carry a credit card balance.

The formula for the interval is:

p'₁±Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }

Z_{1-\alpha /2}= Z_{0.95}= 1.648

0.37±1.648*\sqrt{\frac{0.37*0.63}{1000} }

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂±Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }

0.48±1.648* \sqrt{\frac{0.48*0.52}{1000} }

0.48±1.648*0.016

[0.45;0.51]

With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: \sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015

Seniors: \sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0
3 years ago
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